C++ c++;int开关语句
在过去的一个半小时里,我一直在做一个整数的转换,我知道如何用字符进行转换,但这对我来说似乎很难。任何建议都将被感激。我的问题是,我不能接受这个转换目前所做的超过100分的分数C++ c++;int开关语句,c++,switch-statement,C++,Switch Statement,在过去的一个半小时里,我一直在做一个整数的转换,我知道如何用字符进行转换,但这对我来说似乎很难。任何建议都将被感激。我的问题是,我不能接受这个转换目前所做的超过100分的分数 int testScore; cout <<"Enter your test score and I will tell you \n"; cout <<"the letter grade you earned "; cin
int testScore;
cout <<"Enter your test score and I will tell you \n";
cout <<"the letter grade you earned ";
cin >> testScore;
switch(testScore/10)
{
case 10:
case 9:
cout <<"Your grade is A.\n";
break;
case 8:
cout <<"Your grade is B.\n";
break;
case 7:
cout <<"Your grade is C.\n";
break;
case 6:
cout << "Your grade is D.\n";
break;
case 5:
cout << "Your grade is F.\n";
break;
default:
cout << "That score isn’t valid\n";
}
inttestscore;
cout您正在除以10.0,这是一个双精度数,无法编译。这必须更改为10。
此外,您应该在switch语句之前使用if语句检查它是否在有效范围内
#include<iostream>
#include<iomanip>
using namespace std;
int main()
{
int testScore;
cout <<"Enter your test score and I will tell you \n";
cout <<"the letter grade you earned \n";
cin >> testScore;
if (testScore<=100 && testScore>=0)
switch(testScore/10)
{
case 10:
case 9:
cout <<"Your grade is A.\n";
break;
case 8:
cout <<"Your grade is B.\n";
break;
case 7:
cout <<"Your grade is C.\n";
break;
case 6:
cout << "Your grade is D.\n";
break;
case 5:
cout << "Your grade is F.\n";
break;
default:
cout << "That score isn’t valid\n";
}
else
cout <<"That score isn't valid\n";
return 0;
}
#包括
#包括
使用名称空间std;
int main()
{
int测试分数;
我只是决定这样做,谢谢你的回答
int testScore;
cout <<"Enter your test score and I will tell you \n";
cout <<"the letter grade you earned ";
cin >> testScore;
if (testScore >= 0 && testScore <=100)
{
switch(testScore/10)
{
case 10:
case 9:
cout <<"Your grade is A.\n";
break;
case 8:
cout <<"Your grade is B.\n";
break;
case 7:
cout <<"Your grade is C.\n";
break;
case 6:
cout << "Your grade is D.\n";
break;
default:
cout << "Your grade is F.\n";
}
}
else
cout <<"That score isn't valid" << endl;
inttestscore;
cout您真的应该使用“if”而不是“switch”来执行此操作。类似于以下代码(未测试):
if(testScore>=0&&testScore=90)
等级=‘A’;
否则如果(测试分数>=80)
等级=‘B’;
否则如果(测试分数>=70)
等级=‘C’;
否则如果(测试分数>=60)
等级='D';
其他的
等级=‘F’;
我尝试了这个,它仍然显示了一个A级的数字100-109,这应该是一个注释,这不能回答这个问题。C++(和许多其他语言),将整数109
除以整数10
返回10
,这将触发第一个案例
。如果您不希望人们输入大于100的数字,您需要在某个地方强制执行。例如,在您使用的cin
行和开关
状态之间t、 很公平。不过,在回答这个问题时,可以使用if语句if(testScore=0)如果为true,则执行switch语句;如果为true,则输出测试分数无效false@Borat.sagdiyev你应该把它放在你的答案中。一个浮点数上的开关,所以我不确定它如何能够接受超过100的分数。如果你需要检查值的范围,开关通常是错误的工作工具。你认为inpu会发生什么t为“90”?分数为110将导致案例
值为11,除默认
案例外,您没有考虑该值。
if (testScore >=0 && testScore <= 100)
{
char grade;
if (testScore >= 90)
grade = 'A';
else if (testScore >= 80)
grade = 'B';
else if (testScore >= 70)
grade = 'C';
else if (testScore >= 60)
grade = 'D';
else
grade = 'F';
cout << "Your grade is " << grade << endl;
}
else
{
cout << "Score of " << testScore << " is not valid" << endl;
}