C# PHP文件未收到$\u POST

我的C#代码有问题，它将登录表单中的数据发布到PHP页面上进行验证

在我的开发页面上，它工作正常，但当我切换到生产页面时，它停止工作。（两个网页位于同一台服务器上）

我的登录页面（开发）如下所示：

$user = DB_Login($_POST["username"], $_POST["password"]);
if (!is_null($user))
{
SetLoginCookies($user["userID"], $user["sessionID"]);
echo "valid";
}
else
echo "invalid";

$responseArray = DB_Login($_POST["username"], $_POST["password"]);

if (is_null($responseArray))
{
    die("invalid");
}

private void Login_Click(object sender, RoutedEventArgs e)
    {
        string sendData = "";
        Uri site = new Uri("site");
        WebClient wc = new WebClient();
        wc.Headers[HttpRequestHeader.ContentType] = "application/x-www-form-urlencoded";
        sendData += "username=" + usrname.Text;
        sendData += "&password=" + pword.Password;
        wc.Headers[HttpRequestHeader.ContentLength] = sendData.Length.ToString();
        wc.UploadStringCompleted += new UploadStringCompletedEventHandler(wc_UploadStringCompleted);
        wc.UploadStringAsync(site, "POST", sendData);
    }

    private void wc_UploadStringCompleted(object sender, UploadStringCompletedEventArgs e)
    {
        if (e.Result.Equals("invalid"))
        {
            return;
        }
        else
        {
            MessageBox.Show(e.Result.ToString());

            //Navigate to next page
            NavigationService.Navigate(new Uri("/ControlPanel.xaml", UriKind.Relative));
        }
    }

function DB_Login($username, $password)
{
$password = md5($password);
$username = mysql_escape_string($username);

$request = DB_ExecuteQuery("SELECT userID, isAdmin
    FROM accounts
    WHERE username = '$username' AND password = '$password'");
if ($request->num_rows == 0)
    return NULL;

$requestArray = $request->fetch_array();

$response = array("userID" => $requestArray["userID"]);
$response["sessionID"] = mysql_escape_string(generateGuid());
$response["isAdmin"] = $requestArray["isAdmin"];

DB_ExecuteQuery("UPDATE accounts
    SET sessionID = '". $response['sessionID'] ."'
    WHERE userID = ". $response['userID']);

DB_SetLastLogin($requestArray['userID']);

return $response;
}

我的制作页面如下所示：

$user = DB_Login($_POST["username"], $_POST["password"]);
if (!is_null($user))
{
SetLoginCookies($user["userID"], $user["sessionID"]);
echo "valid";
}
else
echo "invalid";

$responseArray = DB_Login($_POST["username"], $_POST["password"]);

if (is_null($responseArray))
{
    die("invalid");
}

private void Login_Click(object sender, RoutedEventArgs e)
    {
        string sendData = "";
        Uri site = new Uri("site");
        WebClient wc = new WebClient();
        wc.Headers[HttpRequestHeader.ContentType] = "application/x-www-form-urlencoded";
        sendData += "username=" + usrname.Text;
        sendData += "&password=" + pword.Password;
        wc.Headers[HttpRequestHeader.ContentLength] = sendData.Length.ToString();
        wc.UploadStringCompleted += new UploadStringCompletedEventHandler(wc_UploadStringCompleted);
        wc.UploadStringAsync(site, "POST", sendData);
    }

    private void wc_UploadStringCompleted(object sender, UploadStringCompletedEventArgs e)
    {
        if (e.Result.Equals("invalid"))
        {
            return;
        }
        else
        {
            MessageBox.Show(e.Result.ToString());

            //Navigate to next page
            NavigationService.Navigate(new Uri("/ControlPanel.xaml", UriKind.Relative));
        }
    }

function DB_Login($username, $password)
{
$password = md5($password);
$username = mysql_escape_string($username);

$request = DB_ExecuteQuery("SELECT userID, isAdmin
    FROM accounts
    WHERE username = '$username' AND password = '$password'");
if ($request->num_rows == 0)
    return NULL;

$requestArray = $request->fetch_array();

$response = array("userID" => $requestArray["userID"]);
$response["sessionID"] = mysql_escape_string(generateGuid());
$response["isAdmin"] = $requestArray["isAdmin"];

DB_ExecuteQuery("UPDATE accounts
    SET sessionID = '". $response['sessionID'] ."'
    WHERE userID = ". $response['userID']);

DB_SetLastLogin($requestArray['userID']);

return $response;
}

这是非常相似的，但我不明白为什么我的生产页面从不接收POST变量，它总是死

我的C#代码（其中一页）如下所示：

$user = DB_Login($_POST["username"], $_POST["password"]);
if (!is_null($user))
{
SetLoginCookies($user["userID"], $user["sessionID"]);
echo "valid";
}
else
echo "invalid";

$responseArray = DB_Login($_POST["username"], $_POST["password"]);

if (is_null($responseArray))
{
    die("invalid");
}

private void Login_Click(object sender, RoutedEventArgs e)
    {
        string sendData = "";
        Uri site = new Uri("site");
        WebClient wc = new WebClient();
        wc.Headers[HttpRequestHeader.ContentType] = "application/x-www-form-urlencoded";
        sendData += "username=" + usrname.Text;
        sendData += "&password=" + pword.Password;
        wc.Headers[HttpRequestHeader.ContentLength] = sendData.Length.ToString();
        wc.UploadStringCompleted += new UploadStringCompletedEventHandler(wc_UploadStringCompleted);
        wc.UploadStringAsync(site, "POST", sendData);
    }

    private void wc_UploadStringCompleted(object sender, UploadStringCompletedEventArgs e)
    {
        if (e.Result.Equals("invalid"))
        {
            return;
        }
        else
        {
            MessageBox.Show(e.Result.ToString());

            //Navigate to next page
            NavigationService.Navigate(new Uri("/ControlPanel.xaml", UriKind.Relative));
        }
    }

function DB_Login($username, $password)
{
$password = md5($password);
$username = mysql_escape_string($username);

$request = DB_ExecuteQuery("SELECT userID, isAdmin
    FROM accounts
    WHERE username = '$username' AND password = '$password'");
if ($request->num_rows == 0)
    return NULL;

$requestArray = $request->fetch_array();

$response = array("userID" => $requestArray["userID"]);
$response["sessionID"] = mysql_escape_string(generateGuid());
$response["isAdmin"] = $requestArray["isAdmin"];

DB_ExecuteQuery("UPDATE accounts
    SET sessionID = '". $response['sessionID'] ."'
    WHERE userID = ". $response['userID']);

DB_SetLastLogin($requestArray['userID']);

return $response;
}

有什么想法吗

更新：

DB_登录函数如下所示：

$user = DB_Login($_POST["username"], $_POST["password"]);
if (!is_null($user))
{
SetLoginCookies($user["userID"], $user["sessionID"]);
echo "valid";
}
else
echo "invalid";

$responseArray = DB_Login($_POST["username"], $_POST["password"]);

if (is_null($responseArray))
{
    die("invalid");
}

private void Login_Click(object sender, RoutedEventArgs e)
    {
        string sendData = "";
        Uri site = new Uri("site");
        WebClient wc = new WebClient();
        wc.Headers[HttpRequestHeader.ContentType] = "application/x-www-form-urlencoded";
        sendData += "username=" + usrname.Text;
        sendData += "&password=" + pword.Password;
        wc.Headers[HttpRequestHeader.ContentLength] = sendData.Length.ToString();
        wc.UploadStringCompleted += new UploadStringCompletedEventHandler(wc_UploadStringCompleted);
        wc.UploadStringAsync(site, "POST", sendData);
    }

    private void wc_UploadStringCompleted(object sender, UploadStringCompletedEventArgs e)
    {
        if (e.Result.Equals("invalid"))
        {
            return;
        }
        else
        {
            MessageBox.Show(e.Result.ToString());

            //Navigate to next page
            NavigationService.Navigate(new Uri("/ControlPanel.xaml", UriKind.Relative));
        }
    }

function DB_Login($username, $password)
{
$password = md5($password);
$username = mysql_escape_string($username);

$request = DB_ExecuteQuery("SELECT userID, isAdmin
    FROM accounts
    WHERE username = '$username' AND password = '$password'");
if ($request->num_rows == 0)
    return NULL;

$requestArray = $request->fetch_array();

$response = array("userID" => $requestArray["userID"]);
$response["sessionID"] = mysql_escape_string(generateGuid());
$response["isAdmin"] = $requestArray["isAdmin"];

DB_ExecuteQuery("UPDATE accounts
    SET sessionID = '". $response['sessionID'] ."'
    WHERE userID = ". $response['userID']);

DB_SetLastLogin($requestArray['userID']);

return $response;
}

var_dump（$_POST[“username”]，$_POST[“password”]）的结果为NULL和NULL

更新2：

$print\u r（$\u服务器）的结果：

---

嗯，我认为您应该在标题中获得POST方法，而不是get方法。

尝试查找

method="post"

在您的

标签中，或其他任何内容。如果你看到像

method="get"

。。。那是你的问题。将方法更改为post

UploadStringAsync

函数send string作为原始数据，它无法在$\u POST数组中看到 在中，php代码使用

file_get_contents('php://input')

要接收，或使用C#

---

只需一句注释：

$var==NULL

比

is\u NULL（$var）

快得多，效率也更高。我们谈论的是微秒，但仍然值得注意。我们可以看看您的

DB\u Login（）

功能吗？另外，

var_dump（$_POST[“username”]，$_POST[“password”]）是什么显示？是否
isset（$\u POST）
返回true？如果是这样，请尝试
var\u dump（$\u POST）
检查其contents@optimusprime619
isset（$\u POST）
（我想）总是返回true-您想检查
！空（$\u POST）
instead@DaveRandom好的，全局属性始终存在，并且不必为
NULL
，然后为
！空（$\u POST）
它是。。谢谢你的关注好的，我会用var_转储的结果更新我的问题