C# 将T4生成的文件包含在模板文件的同一文件夹中
我正在尝试将保存的文件添加到T4模板文件的当前项目中。 文件按预期通过C# 将T4生成的文件包含在模板文件的同一文件夹中,c#,visual-studio,t4,C#,Visual Studio,T4,我正在尝试将保存的文件添加到T4模板文件的当前项目中。 文件按预期通过SaveOutput方法保存,但当我使用IncludeInCurrentProject方法时,该方法调用ProjectItems.AddFromFile(),然后将文件添加到项目的根 我希望将由SaveOutput方法生成的文件包含在项目的确切位置上 这就是我现在拥有的: 这是我的.tt文件: <#@ template debug="true" hostspecific="true" language="C#" #&g
SaveOutput
方法保存,但当我使用IncludeInCurrentProject
方法时,该方法调用ProjectItems.AddFromFile
(),然后将文件添加到项目的根
我希望将由SaveOutput
方法生成的文件包含在项目的确切位置上
这就是我现在拥有的:
这是我的.tt文件:
<#@ template debug="true" hostspecific="true" language="C#" #>
<#@ output extension=".sql" #>
<#@ assembly name="Microsoft.VisualBasic.dll" #>
<#@ assembly name="EnvDTE" #>
<#@ import Namespace="System.IO" #>
<#@ import namespace="EnvDTE" #>
<#
var MigrationName = Microsoft.VisualBasic.Interaction.InputBox("InputBox Label", "Description");
if (string.IsNullOrWhiteSpace(MigrationName))
return "";
var MigrationVersion = System.DateTime.Now.ToString("yyyyMMddHHmm");
var MigrationFileName = MigrationVersion + "-" + MigrationName + ".sql";
var MigrationFilePath = Path.GetFullPath(Path.Combine(Path.GetDirectoryName(Host.TemplateFile), "", MigrationFileName));
#>
My T4 template goes here
<#
SaveOutput(MigrationFilePath);
IncludeInCurrentProject(MigrationFilePath)
.Open(Constants.vsViewKindPrimary)
.Activate();
#>
<#+
private void SaveOutput(string filename)
{
File.WriteAllText(filename, GenerationEnvironment.ToString());
GenerationEnvironment.Clear();
}
private ProjectItem IncludeInCurrentProject(string filename)
{
return CurrentProject.ProjectItems.AddFromFile(filename);
}
private Project CurrentProject
{
get
{
if (_currentProject == null) {
var serviceProvider = (IServiceProvider)this.Host;
var dte = serviceProvider.GetService(typeof(DTE)) as DTE;
foreach(Project project in dte.Solution.Projects)
{
// workaround. dte.Solution.FindProjectItem(Host.TemplateFile).ContainingProject didn't work
string projectPath = project.FullName.Replace("\\" + project.FileName, string.Empty);
if(Host.TemplateFile.Contains(projectPath))
{
_currentProject = project;
break;
}
}
}
return _currentProject;
}
}
private Project _currentProject;
#>
我的T4模板在这里
调用IncludeInCurrentProject时,输入应为路径+文件名 CurrentProject.ProjectItems
始终引用根目录中的ProjectItems
我使用文件路径浏览ProjectItems
,并调用正确的AddFromFile
。您可以检查GetCurrentProjectItem
方法,该行为在那里实现
现在,模板工作正常:
<#@ template debug="true" hostspecific="true" language="C#" #>
<#@ output extension=".sql" #>
<#@ assembly name="Microsoft.VisualBasic.dll" #>
<#@ assembly name="EnvDTE" #>
<#@ import Namespace="System.IO" #>
<#@ import Namespace="System.Text.RegularExpressions" #>
<#@ import namespace="EnvDTE" #>
<#
var migrationName = Microsoft.VisualBasic.Interaction.InputBox("InputBox Label", "Description");
Regex alphaNumericRegex = new Regex("[^a-zA-Z0-9-_]");
migrationName = alphaNumericRegex.Replace(migrationName, string.Empty);
if (string.IsNullOrWhiteSpace(migrationName))
return "";
var migrationVersion = System.DateTime.Now.ToString("yyyyMMddHHmm");
var migrationFileName = migrationVersion + "-InsertCourt" + migrationName + ".sql";
var migrationFilePath = Path.GetFullPath(Path.Combine(Path.GetDirectoryName(Host.TemplateFile), migrationFileName));
#>
My T4 template goes here
<#
SaveOutput(migrationFilePath);
IncludeInCurrentProject(migrationFilePath)
.Open(Constants.vsViewKindPrimary)
.Activate();
#>
<#+
private void SaveOutput(string filename)
{
File.WriteAllText(filename, GenerationEnvironment.ToString());
GenerationEnvironment.Clear();
}
private ProjectItem IncludeInCurrentProject(string filename)
{
ProjectItem item = GetCurrentProjectItem().ProjectItems.AddFromFile(filename);
item.Properties.Item("BuildAction").Value = "None";
return item;
}
private ProjectItem GetCurrentProjectItem()
{
var serviceProvider = (IServiceProvider)this.Host;
var dte = serviceProvider.GetService(typeof(DTE)) as DTE;
string templateDirectory = Path.GetDirectoryName(Host.TemplateFile);
string foldersString = templateDirectory.Replace(Path.GetDirectoryName(GetCurrentProject().FullName), string.Empty);
string[] foldersArray = foldersString.Split(new [] {"\\"}, StringSplitOptions.RemoveEmptyEntries);
foreach(Project project in dte.Solution.Projects)
{
ProjectItems currentProjectItems = null;
foreach(string folder in foldersArray)
{
if(currentProjectItems == null)
{
currentProjectItems = project.ProjectItems;
}
foreach(ProjectItem projectItem in currentProjectItems)
{
if(projectItem.Name == folder)
{
if(Array.IndexOf(foldersArray, folder) == foldersArray.Length - 1)
{
return projectItem;
}
currentProjectItems = projectItem.ProjectItems;
break;
}
}
}
}
return null;
}
private Project GetCurrentProject()
{
var serviceProvider = (IServiceProvider)this.Host;
var dte = serviceProvider.GetService(typeof(DTE)) as DTE;
foreach(Project project in dte.Solution.Projects)
{
// workaround. dte.Solution.FindProjectItem(Host.TemplateFile).ContainingProject didn't work
string directory = Path.GetDirectoryName(project.FullName);
if(Host.TemplateFile.Contains(directory))
{
return project;
}
}
return null;
}
private ProjectItem _currentProjectItem;
#>
我的T4模板在这里
你好,佩德罗。MigrationFilePath包含完整路径(路径+文件名),此变量发送到IncludeInCurrentProject方法。请在此查看:并根据您的需要进行调整。因此,我也在此处将每个输出写入不同的项目和文件夹:我遇到了完全相同的问题,但在从另一个项目创建文件时遇到了同样的问题。我用了你的文件夹循环解决方案,效果很好。谢谢@安德里亚,我很高兴这个解决方案对你有所帮助。