C# 可以将Json.Net嵌入到可执行文件中吗？

我将

Netwonsoft.Json

库的“嵌入互操作类型”属性设置为

true

，它返回一个错误：

Cannot embed interop types from assembly
'c:\path\packages\Newtonsoft.Json.9.0.1\lib\net45\Newtonsoft.Json.dll'
because it is missing either the 'ImportedFromTypeLibAttribute' attribute or
the 'PrimaryInteropAssemblyAttribute' attribute
c:\path\packages\Newtonsoft.Json.9.0.1\lib\net45\Newtonsoft.Json.dll

---

它看起来像是在

Newtonsoft.Json

库中查找缺少的引用，但我不能完全确定。有没有可能将

Json.Net

嵌入到可执行文件中？

您没有说您使用的是哪种语言，但下面是如何为C语言执行的#

---

首先，关闭“嵌入互操作类型”

然后，在主可执行项目中，卸载并编辑.csproj文件，并在以下行下方：

<Import Project="$(MSBuildToolsPath)\Microsoft.CSharp.targets" />

最后，确保将主应用程序的目标方法更新为刚才添加的项目的主方法

来源：

 <Target Name="AfterResolveReferences">
  <ItemGroup>
    <EmbeddedResource Include="@(ReferenceCopyLocalPaths)" Condition="'%(ReferenceCopyLocalPaths.Extension)' == '.dll'">
      <LogicalName>%(ReferenceCopyLocalPaths.DestinationSubDirectory)%(ReferenceCopyLocalPaths.Filename)%(ReferenceCopyLocalPaths.Extension)</LogicalName>
    </EmbeddedResource>
  </ItemGroup>
</Target>

[STAThread]
public static void Main()
{
    AppDomain.CurrentDomain.AssemblyResolve += OnResolveAssembly;

    App.Main(); // Run WPF startup code.
}

private static Assembly OnResolveAssembly(object sender, ResolveEventArgs e)
{
    var thisAssembly = Assembly.GetExecutingAssembly();

    // Get the Name of the AssemblyFile
    var assemblyName = new AssemblyName(e.Name);
    var dllName = assemblyName.Name + ".dll";

    // Load from Embedded Resources - This function is not called if the Assembly is already
    // in the same folder as the app.
    var resources = thisAssembly.GetManifestResourceNames().Where(s => s.EndsWith(dllName));
    if (resources.Any())
    {

        // 99% of cases will only have one matching item, but if you don't,
        // you will have to change the logic to handle those cases.
        var resourceName = resources.First();
        using (var stream = thisAssembly.GetManifestResourceStream(resourceName))
        {
            if (stream == null) return null;
            var block = new byte[stream.Length];

            // Safely try to load the assembly.
            try
            {
                stream.Read(block, 0, block.Length);
                return Assembly.Load(block);
            }
            catch (IOException)
            {
                return null;
            }
            catch(BadImageFormatException)
            {
                return null;
            }
        }
    }

    // in the case the resource doesn't exist, return null.
    return null;
}