C# 为什么我不能在combobox中获得实际的选定值？

我有两个组合框

cmbfrom

和

cmbdest

从SQL数据库检索数据并将其设置为组合框值的代码如下：

databaseserver ser = new databaseserver();
SqlConnection con = new SqlConnection(ser.dbserver + "Initial Catalog=AirlinesDB;Integrated Security=True");
con.Open(); 
SqlDataAdapter citiesadp = new SqlDataAdapter("select city from cities",con);
DataSet dset = new DataSet(); //Creating instance of DataSet
citiesadp.Fill(dset,"cities");
cmbfrom.DataSource = dset.Tables["cities"];
cmbfrom.DisplayMember = "city";
con.Close();

SqlConnection con1 = new SqlConnection(ser.dbserver + "Initial Catalog=AirlinesDB;Integrated Security=True");
con1.Open();
SqlDataAdapter destcity = new SqlDataAdapter("select city from cities",con1);
DataSet destset = new DataSet();
destcity.Fill(destset,"cities");
cmbdest.DataSource = destset.Tables["cities"];
cmbdest.DisplayMember = "city";
con1.Close();

但是，当我在

cmbdest

中选择一个值时，它返回的是

System.Data.DataRowView

，而不是实际值

从组合框中检索选定值的代码如下：

textBox1.Text = cmbdest.SelectedValue.ToString();
textBox2.Text = cmbfrom.SelectedValue.ToString();

---

我从第一个组合（即所选城市名称）中获取实际值，但第二个组合获取值：

System.Data.DataRowView

您应该首先为

cmbfrom

设置属性

ValueMember

，请尝试以下代码：

    databaseserver ser = new databaseserver();
    SqlConnection con = new SqlConnection(ser.dbserver + "Initial Catalog=AirlinesDB;Integrated Security=True");
    con.Open(); 
    SqlDataAdapter citiesadp = new SqlDataAdapter("select city from cities",con);
    DataSet dset = new DataSet(); //Creating instance of DataSet
    citiesadp.Fill(dset,"cities");
    cmbfrom.DataSource = dset.Tables["cities"];
    cmbfrom.DisplayMember = "city";
    cmbfrom..ValueMember= "city";

    con.Close();

    SqlConnection con1 = new SqlConnection(ser.dbserver + "Initial Catalog=AirlinesDB;Integrated Security=True");
    con1.Open();
    SqlDataAdapter destcity = new SqlDataAdapter("select city from cities",con1);
    DataSet destset = new DataSet();
    destcity.Fill(destset,"cities");
    cmbdest.DataSource = destset.Tables["cities"];
    cmbdest.DisplayMember = "city";
    cmbdest..ValueMember= "city";
    con1.Close();

---

尝试从中选择

CMB，然后会发生什么？然后是“cmbdest”的值是
System.Data.DataRowView.
？否。。他们在组合框中得到了真实的城市名称，比如迪拜、孟买、洛杉矶等等，和什么一样？不明白你说的话吗？我对CMB没有任何问题。从它的工作来看，问题在于CMB。请不要使用“试试这个”表格。相反，解释为什么OP应该遵循你的建议以及他问题的原因。请更正代码，它有一些错误。