C# 根据不同名称的字符串属性相交2种不同类型的集合

我收集了两种不同的物品

我正在尝试基于字符串属性进行.Intersect

public class EmployeeDto
{
    public string SSN { get; set; }
    public DateTime HireDate { get; set; }
}


public class PersonDto
{
    public string SocialSecurityNumber { get; set; }
    public string Name { get; set; }
}

尝试：

            ICollection<EmployeeDto> empsColl = new List<EmployeeDto>();
            empsColl.Add(new EmployeeDto() { SSN = "222-22-2222", HireDate = DateTime.Now });
            empsColl.Add(new EmployeeDto() { SSN = "333-33-3333", HireDate = DateTime.Now });
            empsColl.Add(new EmployeeDto() { SSN = "444-44-4444", HireDate = DateTime.Now });
            empsColl.Add(new EmployeeDto() { SSN = "555-55-5555", HireDate = DateTime.Now });


            ICollection<PersonDto> pers = new List<PersonDto>();

            pers.Add(new PersonDto() { SocialSecurityNumber = "333-33-3333", Name = "John" });
            pers.Add(new PersonDto() { SocialSecurityNumber = "444-44-4444", Name = "Mary" });



            ICollection<EmployeeDto> overlap1 = empsColl.Where(api => api.SSN.Any(val => val.Equals(pers.Any(cl => cl.SocialSecurityNumber.Equals(val))))).ToList();

 ICollection<EmployeeDto> overlap2 = empsColl.Where(api => api.SSN.Equals(pers.Any(per => per.SocialSecurityNumber.Equals(api.SSN, StringComparison.OrdinalIgnoreCase)))).ToList();



            foreach (EmployeeDto emp in overlap1)
            {
                Console.WriteLine(emp.SSN);
            }

ICollection empsColl=new List（）；
Add（newemployeedto（）{SSN=“222-22-2222”，HireDate=DateTime.Now}）；
添加（newemployeedto（）{SSN=“333-33-3333”，HireDate=DateTime.Now}）；
添加（newemployeedto（）{SSN=“444-44-4444”，HireDate=DateTime.Now}）；
Add（newemployeedto（）{SSN=“555-55-5555”，HireDate=DateTime.Now}）；
ICollection pers=新列表（）；
pers.Add（newpersondto（）{SocialSecurityNumber=“333-33-3333”，Name=“John”}）；
pers.Add（newpersondto（）{SocialSecurityNumber=“444-44-4444”，Name=“Mary”}）；
ICollection overlap1=empsColl.Where（api=>api.SSN.Any（val=>val.Equals（pers.Any）（cl=>cl.SocialSecurityNumber.Equals（val '））.ToList（）；
ICollection overlap2=empsColl.Where（api=>api.SSN.Equals（per.Any（per=>per.SocialSecurityNumber.Equals（api.SSN，StringComparison.OrdinalIgnoreCase）））.ToList（）；
foreach（雇员在重叠1中加入emp）
{
控制台写入线（emp.SSN）；
}

理想的结果是一个

i集合

，其中包含333-33-3333和444-44-4444的EmployeeDto对象

---

谢谢。

以下是如何做到这一点：

var overlap = empsColl.Where(e => pets.Any(p => p.SocialSecurityNumber == e.SSN)).ToList();

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以下是如何做到这一点：

var overlap = empsColl.Where(e => pets.Any(p => p.SocialSecurityNumber == e.SSN)).ToList();

---

我想这样就行了

    empsColl.Where(ec => pers.Select(p => p.SocialSecurityNumber).Contains(ec.SSN)));

---

我想这样就行了

    empsColl.Where(ec => pers.Select(p => p.SocialSecurityNumber).Contains(ec.SSN)));

这应该行得通

    var result =  empsColl.Where(x => pers.Any(y=> string.Compare(y.SocialSecurityNumber, x.SSN) == 0));

这应该行得通

    var result =  empsColl.Where(x => pers.Any(y=> string.Compare(y.SocialSecurityNumber, x.SSN) == 0));

ICollection overlap4=empsColl.Where（e=>pers.Any（p=>p.SocialSecurityNumber.Equals（e.SSN，StringComparison.OrdinalIgnoreCase）））.ToList（）；ICollection overlap4=empsColl.Where（e=>pers.Any（p=>p.SocialSecurityNumber.Equals（e.SSN，StringComparison.OrdinalIgnoreCase）））.ToList（）；