C# 使用DevExpress WinForm管理的资源

我正在尝试创建一个带有嵌入式资源的exe。一切正常，但如果DevExpress.Utils.dll与.exe不在同一文件夹中，应用程序将崩溃！ 虽然所有的dll文件都作为嵌入式资源包含，我引用了它们。 奇怪的是，它只有DevExpress.Utils.dll。 未找到的DLL我正在加载以下内容：

[STAThread]
  static void Main()
  {
     AppDomain.CurrentDomain.AssemblyResolve += CurrentDomainOnAssemblyResolve;

      Application.EnableVisualStyles();
      Application.SetCompatibleTextRenderingDefault(false);
      Application.Run(new MyForm());
  }

  private static Assembly CurrentDomainOnAssemblyResolve(object sender, ResolveEventArgs args)
  {
    // the ddls are in a lib folder.
     String resourceName = "MyApplication." + "lib." + new AssemblyName(args.Name).Name + ".dll";

     using (var stream = Assembly.GetExecutingAssembly().GetManifestResourceStream(resourceName))
     {
        if (stream != null)
        {
           Byte[] assemblyData = new Byte[stream.Length];


           stream.Read(assemblyData, 0, assemblyData.Length);


           return Assembly.Load(assemblyData);
        }
     }
     return null;
  }

---

对于遇到此问题的任何人：

DevExpress：“CLR尝试验证主方法中的代码。由于该方法包含DevExpress类型，CLR尝试加载包含此类型的相应程序集，但失败，因为该程序集不存在于.exe文件所在的文件夹中。”

[STAThread]
static void Main()
{
 AppDomain.CurrentDomain.AssemblyResolve += CurrentDomainOnAssemblyResolve;

  Application.EnableVisualStyles();
  Application.SetCompatibleTextRenderingDefault(false);
  Application.Run(ReturnXtraForm());
}

private static Assembly CurrentDomainOnAssemblyResolve(object sender,   ResolveEventArgs args)
{
// the ddls are in a lib folder.
 String resourceName = "MyApplication." + "lib." + new AssemblyName(args.Name).Name + ".dll";

 using (var stream = Assembly.GetExecutingAssembly().GetManifestResourceStream(resourceName))
 {
    if (stream != null)
    {
       Byte[] assemblyData = new Byte[stream.Length];


       stream.Read(assemblyData, 0, assemblyData.Length);


       return Assembly.Load(assemblyData);
    }
 }
 return null;
}

private static Form ReturnXtraForm() {
      DevExpress.Skins.SkinManager.EnableFormSkins();
      UserLookAndFeel.Default.SetSkinStyle("DevExpress Style");
      return new MyForm();
  }