如何在不改变c#中的功能的情况下尽可能减少代码中的分支?
有一些可能缩短您的代码:如何在不改变c#中的功能的情况下尽可能减少代码中的分支?,c#,branch,C#,Branch,有一些可能缩短您的代码: 您可以使用do{}while(条件)循环。这样,您就可以决定在输入之后是否离开循环 您不需要一个变量来决定是否停止循环。您可以在循环条件中检查所有条件(在您的情况下非常容易) 您可以使用正则表达式检查字符串的长度,使用^=字符串的开头和$=字符串的结尾锚定和{5}作为匹配长度 您还可以简化正则表达式以忽略该情况 您的除法操作似乎只是检查输入的第一个数字是否与0不同。您还可以使用正则表达式检查这一点 您可以使用staticRegex.IsMatch()方法,该方法返回tr
do{}while(条件)代码>循环。这样,您就可以决定在输入之后是否离开循环
^
=字符串的开头和$
=字符串的结尾锚定和{5}
作为匹配长度0
不同。您还可以使用正则表达式检查这一点Regex.IsMatch()
方法,该方法返回true
或false
public static void addpatron()
{
Console.WriteLine("You have selected to add a Patron.");
string first, last, city, state = "", street, email, temp;
int zip = 0;
long number = 0;
Console.WriteLine("Please Provide a First Name: ");
first = Console.ReadLine();
Console.WriteLine("Please Provide a Last Name: ");
last = Console.ReadLine();
Console.WriteLine("Please Provide a Street Address: ");
street = Console.ReadLine();
Console.WriteLine("Please Provide a City Name: ");
city = Console.ReadLine();
Console.WriteLine("Please Provide a Email Id: ");
email = Console.ReadLine();
int f = 0;
while (f == 0)
{
Console.WriteLine("Please Provide a State Name: ");
state = Console.ReadLine();
if (state.Length == 2)
{
Regex r = new Regex(@"([A-Za-z][A-Za-z])");
Match m = r.Match(state);
if (m.Success)
f = 1;
}
}
while (f == 1)
{
Console.WriteLine("Please Provide a Zip Code: ");
temp = Console.ReadLine();
if (temp.Length == 5)
{
Regex r = new Regex(@"([0-9]{5})");
Match m = r.Match(temp);
if (m.Success)
{
zip = int.Parse(temp);
if (zip / 10000 != 0)
f = 0;
}
}
}
while (f == 0)
{
Console.WriteLine("Please Provide a Mobile Number: ");
temp = Console.ReadLine();
if (temp.Length == 10)
{
Regex r = new Regex(@"([0-9]{10})");
Match m = r.Match(temp);
if (m.Success)
{
number = long.Parse(temp);
if (number / 100000000 != 0)
f = 1;
}
}
}
MainClass.patron.Add(MainClass.user, new Info { firstname = first, lastname = last, street = street, state = state, city = city, zip = zip, phone = number, email = email });
displayUser.display(MainClass.user);
MainClass.user++;
MainClass.Menu();
}
检查邮政编码int.TryParse()
仅在Regex.Match()
返回true
并且是解析和分配表达式中的值的方便方法时才会执行
do {
Console.WriteLine("Please Provide a State Name: ");
state = Console.ReadLine();
} while (!RegEx.IsMatch(state, @"^[a-z]{2}$", RegexOptions.IgnoreCase))
有一些可能缩短您的代码:
do{}while(条件)代码>循环。这样,您就可以决定在输入之后是否离开循环
^
=字符串的开头和$
=字符串的结尾锚定和{5}
作为匹配长度0
不同。您还可以使用正则表达式检查这一点Regex.IsMatch()
方法,该方法返回true
或false
public static void addpatron()
{
Console.WriteLine("You have selected to add a Patron.");
string first, last, city, state = "", street, email, temp;
int zip = 0;
long number = 0;
Console.WriteLine("Please Provide a First Name: ");
first = Console.ReadLine();
Console.WriteLine("Please Provide a Last Name: ");
last = Console.ReadLine();
Console.WriteLine("Please Provide a Street Address: ");
street = Console.ReadLine();
Console.WriteLine("Please Provide a City Name: ");
city = Console.ReadLine();
Console.WriteLine("Please Provide a Email Id: ");
email = Console.ReadLine();
int f = 0;
while (f == 0)
{
Console.WriteLine("Please Provide a State Name: ");
state = Console.ReadLine();
if (state.Length == 2)
{
Regex r = new Regex(@"([A-Za-z][A-Za-z])");
Match m = r.Match(state);
if (m.Success)
f = 1;
}
}
while (f == 1)
{
Console.WriteLine("Please Provide a Zip Code: ");
temp = Console.ReadLine();
if (temp.Length == 5)
{
Regex r = new Regex(@"([0-9]{5})");
Match m = r.Match(temp);
if (m.Success)
{
zip = int.Parse(temp);
if (zip / 10000 != 0)
f = 0;
}
}
}
while (f == 0)
{
Console.WriteLine("Please Provide a Mobile Number: ");
temp = Console.ReadLine();
if (temp.Length == 10)
{
Regex r = new Regex(@"([0-9]{10})");
Match m = r.Match(temp);
if (m.Success)
{
number = long.Parse(temp);
if (number / 100000000 != 0)
f = 1;
}
}
}
MainClass.patron.Add(MainClass.user, new Info { firstname = first, lastname = last, street = street, state = state, city = city, zip = zip, phone = number, email = email });
displayUser.display(MainClass.user);
MainClass.user++;
MainClass.Menu();
}
检查邮政编码int.TryParse()
仅在Regex.Match()
返回true
并且是解析和分配表达式中的值的方便方法时才会执行
do {
Console.WriteLine("Please Provide a State Name: ");
state = Console.ReadLine();
} while (!RegEx.IsMatch(state, @"^[a-z]{2}$", RegexOptions.IgnoreCase))
这可能更适合于突破一段时间的循环。使用无意义的
f
变量可以替换为while(true)。。。。。如果(成功)失败代码>这可能更适合于中途中断循环。使用无意义的f
变量可以替换为while(true)。。。。。如果(成功)失败代码>