C# 字符串数组到XML

我在c#中有一个字符串数组，其中包含地址行。阵列中至少有2行，最多有4行。此数组需要转换为需要4个地址元素的XML查询。我就是这样做的，而且很有效，但似乎应该有一个更有效的方法

        switch (address.Length)
        {
            case 2:
                address2[0] = "";
                address2[1] = "";
                address2[2] = address[0];
                address2[3] = address[1];
                break;
            case 3:
                address2[0] = "";
                address2[1] = address[0];
                address2[2] = address[1];
                address2[3] = address[2];
                break;
            case 4:
                address2[0] = address[0];
                address2[1] = address[1];
                address2[2] = address[2];
                address2[3] = address[3];
                break;
            default:
                MessageBox.Show("Invalid Address Block Length");
                break;
        }

这将填充第二个字符串数组，最终创建XML，如：

            "<ADDRESS0>" + address2[0] + "</ADDRESS0>" +
            "<ADDRESS1>" + address2[1] + "</ADDRESS1>" +
            "<ADDRESS2>" + address2[2] + "</ADDRESS2>" +
            "<ADDRESS3>" + address2[3] + "</ADDRESS3>" 

“”+address2[0]+“”+
“+address2[1]”+
“+address2[2]+”+
“+address2[3]”

即使内部文本为空，XML也必须包含4个地址元素。

通过字符串连接创建XML确实不是一个好主意。总有一天你会搞砸的

您可以使用LINQ to XML来创建元素，在数组的前面添加n个额外的空行，总共得到4个：

string[] address = {"first", "second", "third"};

var extra = Math.Max(0, 4 - address.Length);

var elements = Enumerable.Repeat("", extra)
    .Concat(address)
    .Select((line, index) => new XElement("ADDRESS" + index, line));

输出：

<ADDRESS0></ADDRESS0>
<ADDRESS1>first</ADDRESS1>
<ADDRESS2>second</ADDRESS2>
<ADDRESS3>third</ADDRESS3>

通过字符串连接创建XML确实不是一个好主意。总有一天你会搞砸的

您可以使用LINQ to XML来创建元素，在数组的前面添加n个额外的空行，总共得到4个：

string[] address = {"first", "second", "third"};

var extra = Math.Max(0, 4 - address.Length);

var elements = Enumerable.Repeat("", extra)
    .Concat(address)
    .Select((line, index) => new XElement("ADDRESS" + index, line));

输出：

<ADDRESS0></ADDRESS0>
<ADDRESS1>first</ADDRESS1>
<ADDRESS2>second</ADDRESS2>
<ADDRESS3>third</ADDRESS3>

我认为这可能是您在实际生成值时可以做的最有效的事情-但是，您也可以在循环中进行：

var address = new string[]{ "a", "b", "c" };
var address2 = new string[]{ "", "", "", "" };

for (int i = 0; i < address.Length; i++)
{
    address2[address2.Length - i - 1] = address[address.Length - i - 1];
}

var address=新字符串[]{“a”、“b”、“c”}；
var address2=新字符串[]{“”、“”、“”、“”}；
for（int i=0；i
我认为这可能是您在实际生成值时可以做的最有效的事情-但是，您也可以在循环中进行：

var address = new string[]{ "a", "b", "c" };
var address2 = new string[]{ "", "", "", "" };

for (int i = 0; i < address.Length; i++)
{
    address2[address2.Length - i - 1] = address[address.Length - i - 1];
}

var address=新字符串[]{“a”、“b”、“c”}；
var address2=新字符串[]{“”、“”、“”、“”}；
for（int i=0；i
有一整套称为“查询”xml的功能。它还可以帮助构建XML，有一整套的功能叫做“查询”XML。它还可以帮助构建XML。