C# WCF中的动态对象不可能?
在用WCF(json)构建响应时,我非常确定不可能使用完全动态的对象,但我只是想先在这里仔细检查一下 理想的回答应该是:C# WCF中的动态对象不可能?,c#,wcf,serialization,C#,Wcf,Serialization,在用WCF(json)构建响应时,我非常确定不可能使用完全动态的对象,但我只是想先在这里仔细检查一下 理想的回答应该是: "userTypes" : { "BartSimpson" : { "url" : "foo", "de
"userTypes" :
{
"BartSimpson" :
{
"url" : "foo",
"desc" : "bar"
},
"LisaSimpson" :
{
"url" : "foo",
"desc" : "bar"
}
}
在“编译”代码中,可以通过以下体系结构(稍微伪代码)执行上述操作:
但是我的主要目标是,
BartSimpson
和LisaSimpson
不是“编译”的,因此我可以有任意数量的字符
类,在响应中有任意名称/标识。在服务实现类的顶部使用添加以下(确保在项目中添加正确的引用):
您可以尝试以下输出动态结果的简单方法:
public string GetData()
{
dynamic d = new ExpandoObject();
dynamic bartSimpson = new ExpandoObject();
dynamic lisaSimpson = new ExpandoObject();
bartSimpson.url = "foo";
bartSimpson.desc = "bar";
lisaSimpson.url = "foo";
lisaSimpson.desc = "bar";
d.userTypes = new ExpandoObject();
d.userTypes.BartSimpson = bartSimpson;
d.userTypes.LisaSimpson = lisaSimpson;
var s = JsonSerializer.Create();
var sb = new StringBuilder();
using (var sw = new StringWriter(sb))
{
s.Serialize(sw, d);
}
return sb.ToString();
}
要更进一步(您只需在comaSeparatedNames
值中通过Bart和Lisa),您可以执行以下操作:
public string GetData(string comaSeparatedNames)
{
string[] names = comaSeparatedNames.Split(',');
dynamic d = new ExpandoObject();
dynamic dNames = new ExpandoObject();
foreach (var name in names)
{
dynamic properties = new ExpandoObject();
properties.url = "foo";
properties.desc = "bar";
((IDictionary<string, object>)dNames).Add(name, properties);
}
((IDictionary<string, object>)d).Add("userTypes", dNames);
var s = JsonSerializer.Create();
var sb = new StringBuilder();
using (var sw = new StringWriter(sb))
{
s.Serialize(sw, d);
}
// deserializing sample
//dynamic dummy = new ExpandoObject();
//var instance = s.Deserialize(new StringReader(sb.ToString()),
// dummy.GetType());
//var foo = instance.userTypes.BartSimpson.url;
return sb.ToString();
}
公共字符串GetData(字符串comaSeparatedNames)
{
字符串[]名称=comaSeparatedNames.Split(',');
动态d=新的ExpandooObject();
动态dNames=新的ExpandoObject();
foreach(名称中的变量名称)
{
动态属性=新的ExpandooObject();
properties.url=“foo”;
properties.desc=“bar”;
添加(名称、属性);
}
添加(“用户类型”,dNames);
var s=JsonSerializer.Create();
var sb=新的StringBuilder();
使用(var sw=新的StringWriter(sb))
{
s、 序列化(sw,d);
}
//反序列化样本
//动态虚拟对象=新的ExpandooObject();
//var instance=s.Deserialize(新StringReader(sb.ToString()),
//dummy.GetType());
//var foo=instance.userTypes.BartSimpson.url;
使某人返回字符串();
}
注意:我还提供了行(注释)用于反序列化。Edit:我假设您正在使用Newtonsoft.Json
进行序列化。感谢您提供了如此全面的代码示例。我目前正在研究它。不幸的是,现在我的返回类型定义为字符串,我的响应似乎已转义了所有值。没关系,我在这里找到了解决方案:好的,这是这是一个非常棒的解决方案,非常感谢。我注意到了一些很酷的事情:动态属性也可以按以下方式添加:(d为IDictionary)。添加(“bart simpson”,bart);`Yes-这允许属性之间带有“空格”。而且bart
可以是强类型类,因此您可以将ExpandoObject
与强类型对象混合匹配。
public string GetData()
{
dynamic d = new ExpandoObject();
dynamic bartSimpson = new ExpandoObject();
dynamic lisaSimpson = new ExpandoObject();
bartSimpson.url = "foo";
bartSimpson.desc = "bar";
lisaSimpson.url = "foo";
lisaSimpson.desc = "bar";
d.userTypes = new ExpandoObject();
d.userTypes.BartSimpson = bartSimpson;
d.userTypes.LisaSimpson = lisaSimpson;
var s = JsonSerializer.Create();
var sb = new StringBuilder();
using (var sw = new StringWriter(sb))
{
s.Serialize(sw, d);
}
return sb.ToString();
}
public string GetData(string comaSeparatedNames)
{
string[] names = comaSeparatedNames.Split(',');
dynamic d = new ExpandoObject();
dynamic dNames = new ExpandoObject();
foreach (var name in names)
{
dynamic properties = new ExpandoObject();
properties.url = "foo";
properties.desc = "bar";
((IDictionary<string, object>)dNames).Add(name, properties);
}
((IDictionary<string, object>)d).Add("userTypes", dNames);
var s = JsonSerializer.Create();
var sb = new StringBuilder();
using (var sw = new StringWriter(sb))
{
s.Serialize(sw, d);
}
// deserializing sample
//dynamic dummy = new ExpandoObject();
//var instance = s.Deserialize(new StringReader(sb.ToString()),
// dummy.GetType());
//var foo = instance.userTypes.BartSimpson.url;
return sb.ToString();
}