C# 将泛型对象作为参数加载的操作码

我正在调用一个方法，其中一个参数的类型为object。如何将其加载到堆栈上？我知道枚举有整数等价物，但我也希望使用它将使用Type.CreateInstance创建的实际对象作为参数放入方法addoutput

//method addoutput of type overriden by the typebuilder is of form    addoutput(object o)
//enumType is a Type that is an enumeration
TypeBuilder tb;
//tb is initialized here
//override constructor
ConstructorBuilder ctor1 = tb.DefineConstructor(MethodAttributes.Public,    CallingConventions.Standard, null);
ILGenerator ctor1IL = ctor1.GetILGenerator();
FieldInfo[] infos;
infos = enumType.GetFields(BindingFlags.Public | BindingFlags.Static);
//basically for each value in the enumeration an output is created
foreach (FieldInfo fi in infos)
{
 MethodInfo addoutputinfo = tb.BaseType.GetMethod("addoutput",     BindingFlags.NonPublic | BindingFlags.Public | BindingFlags.Instance |     BindingFlags.Static);
 ctor1IL.Emit(OpCodes.Ldarg_0);
 //something like this ? seems there's a syntax error 
 ctor1IL.Emit(OpCodes.Ldobj,fi.GetValue(null))  
 ctor1IL.Emit(OpCodes.Call, addoutputinfo);
}

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你能提供一个吗？好的，请再次回顾OP，谢谢用C写代码，然后看看ILDASM生成了什么@用户1296193，你能提供你尝试得到的c#等价物吗？addoutput（Enum.EnumValue1）；addoutput（Enum.EnumValue2）。。。。