C#滚动列表视图到更新的项目
我有一个C#滚动列表视图到更新的项目,c#,wpf,C#,Wpf,我有一个列表视图 <ListView x:Name="BlockList" Grid.Row="1" Grid.ColumnSpan="4" ItemsSource="{Binding Blocks}"> <ListView.View> <GridView> <GridViewColumn Width="75" Header="Address" DisplayMemberBi
列表视图
<ListView x:Name="BlockList" Grid.Row="1" Grid.ColumnSpan="4" ItemsSource="{Binding Blocks}">
<ListView.View>
<GridView>
<GridViewColumn Width="75" Header="Address" DisplayMemberBinding="{Binding Path=Address, Converter={StaticResource IntToHexConverter}}"/>
<GridViewColumn Width="100" Header="Length" DisplayMemberBinding="{Binding Length}"/>
<GridViewColumn Width="100" Header="Status" DisplayMemberBinding="{Binding Status}"/>
</GridView>
</ListView.View>
</ListView>
这些块
最初将以块状态开始。未写入
状态,最终被写入
,然后被验证
。当状态更改时,如何将列表视图
滚动到块
有很多事情需要做
1) 您的块
需要实现INotifyPropertyChanged
public class Block : ObservableObject, INotifyPropertyChanged
{
// Your existing members and code
private BlockStatus _status;
public BlockStatus Status
{
get { return _status; }
set { _status = value; NotifyPropertyChanged("Status"); }
}
// INotifyPropertyChanged implementation
public event PropertyChangedEventHandler PropertyChanged;
protected void NotifyPropertyChanged(string propertyName)
{
if (PropertyChanged != null)
{
PropertyChanged(this, new PropertyChangedEventArgs(propertyName));
}
}
}
2) 您的ViewModel
需要有一个StatusChanged
事件
public delegate void StatusChangedHandler(object sender, StatusChangedHandlerArgs args);
public event StatusChangedHandler StatusChanged;
// Put this class where it suits your project
public class StatusChangedHandlerArgs
{
public Block.BlockStatus NewStatus { get; private set; }
public StatusChangedHandlerArgs(Block.BlockStatus newStatus)
{
NewStatus = newStatus;
}
}
3) 视图模型中的块
属性需要如下所示:
private ObservableCollection<Block> _blocks;
public ObservableCollection<Block> Blocks
{
get
{
return _blocks;
}
set
{
_blocks = value;
if (_blocks != null)
{
foreach (var block in _blocks)
{
block.PropertyChanged += block_PropertyChanged;
}
}
NotifyPropertyChanged("Blocks");
}
}
// The event handler for PropertyChanged
private void block_PropertyChanged(object sender, System.ComponentModel.PropertyChangedEventArgs e)
{
if (e.PropertyName != "Status" || StatusChanged == null)
{
return;
}
var block = sender as Block;
if (block != null)
{
StatusChanged.Invoke(block, new StatusChangedHandlerArgs(block.Status));
}
}
这听起来有点像一个丑陋的解决方案。糟糕的用户体验。用户应该可以不间断地自由滚动,我建议在状态栏中显示最新的状态更新。或者只在写入项目后将其添加到列表框中,每次添加新项目时滚动到底。Glen他的项目有什么不好的地方不由你来决定。将列表项自动滚动到视图中是完全合理的。
private ObservableCollection<Block> _blocks;
public ObservableCollection<Block> Blocks
{
get
{
return _blocks;
}
set
{
_blocks = value;
if (_blocks != null)
{
foreach (var block in _blocks)
{
block.PropertyChanged += block_PropertyChanged;
}
}
NotifyPropertyChanged("Blocks");
}
}
// The event handler for PropertyChanged
private void block_PropertyChanged(object sender, System.ComponentModel.PropertyChangedEventArgs e)
{
if (e.PropertyName != "Status" || StatusChanged == null)
{
return;
}
var block = sender as Block;
if (block != null)
{
StatusChanged.Invoke(block, new StatusChangedHandlerArgs(block.Status));
}
}
// Somewhere in the initializer or constructor for the page
yourViewModel.StatusChanged += yourViewModel_StatusChanged;
// The handler for StatusChanged
private void yourViewModel_StatusChanged(object sender, StatusChangedHandlerArgs args)
{
var block = sender as Block;
if (block != null)
{
BlockList.ScrollIntoView(block);
}
}