C# 在c中基于子数组过滤数组中的重复项#
我有一个带有基本代码的人员列表和一系列位置。我需要删除列表中具有相同位置的不同基本代码的人员,并保留具有不同位置的人员 我尝试使用IEqualityComparer和linq的group by,但没有成功。 你们能告诉我怎么做吗? 这是我的班级结构C# 在c中基于子数组过滤数组中的重复项#,c#,linq,filter,iequalitycomparer,C#,Linq,Filter,Iequalitycomparer,我有一个带有基本代码的人员列表和一系列位置。我需要删除列表中具有相同位置的不同基本代码的人员,并保留具有不同位置的人员 我尝试使用IEqualityComparer和linq的group by,但没有成功。 你们能告诉我怎么做吗? 这是我的班级结构 public class Person { public string Name { get; set; } public List<Location> Locations { get; set; } } public
public class Person
{
public string Name { get; set; }
public List<Location> Locations { get; set; }
}
public class Location
{
public string Name { get; set; }
public string BaseCode { get; set; }
}
我想从我的列表中筛选人员2,并保留人员1和人员3。请注意您可以使用IEquatable接口,并像这样重写Equal和GetHashCode方法: 有问题的更改后编辑:
public class Location : IEquatable<Location>
{
public string Name { get; set; }
public string BaseCode { get; set;
public bool Equals(Location other)
{
if (Object.ReferenceEquals(other, null)) return false;
if (Object.ReferenceEquals(this, other)) return true;
return BaseCode.Equals(other.BaseCode);
}
public override int GetHashCode()
{
return BaseCode.GetHashCode();
}
}
您可以从中了解此接口,Adam的解决方案是更“正确”的处理方式。但是如果您想使用LINQ,那么像这样的东西也应该这样做(注意,代码期望位置是有序的,并将字符串作为标识符):
免责声明:此解决方案不专门处理具有不同/相同位置的相同BaseCode
;你的要求中没有提到这一点。
IEqualityComparer
Route
这里的重要部分是个人和位置的IEqualityComparer
实现:
class Program
{
static void Main(string[] args)
{
var p1 = new Person {Name ="John", BaseCode="AA12", Locations = new List<Location>
{
new Location { Name = "India" },
new Location { Name = "USA" }
}};
var p2 = new Person {Name ="John", BaseCode="AA13", Locations = new List<Location>
{
new Location { Name = "India" },
new Location { Name = "USA" }
}};
var p3 = new Person {Name ="John", BaseCode="AA14", Locations = new List<Location>
{
new Location { Name = "India" },
new Location { Name = "UK" }
}};
var persons = new List<Person> { p1, p2, p3 };
// Will not return p2.
var distinctPersons = persons.Distinct(new PersonComparer()).ToList();
Console.ReadLine();
}
}
public class PersonComparer : IEqualityComparer<Person>
{
public bool Equals(Person x, Person y)
{
if (x == null || y == null)
return false;
bool samePerson = x.Name == y.Name;
bool sameLocations = !x.Locations
.Except(y.Locations, new LocationComparer())
.Any();
return samePerson && sameLocations;
}
public int GetHashCode(Person obj)
{
return obj.Name.GetHashCode();
}
}
public class LocationComparer : IEqualityComparer<Location>
{
public bool Equals(Location x, Location y)
{
if (x == null || y == null)
return false;
return x.Name == y.Name;
}
public int GetHashCode(Location obj)
{
return obj.Name.GetHashCode();
}
}
这将导致一个更简单的调用:
var distinctPersons = persons.Distinct().ToList();
我很想写下面这样的东西。我还没有检查y.Locations.Equals()
是否有效,但是用同样的功能替换它应该很简单
List<Person> personList = new List<Person>();
List<Person> deduplicatedPersonList = new List<Person>();
personList.ForEach(x =>
{
Person existingPerson = personList.Find(y =>
{
if (y.Locations.Equals(x.Locations))
return false;
return true;
});
if (existingPerson == null)
deduplicatedPersonList.Add(x);
});
List personList=new List();
List deduplicatedPersonList=新建列表();
personList.ForEach(x=>
{
Person existingPerson=personList.Find(y=>
{
如果(y位置等于(x位置))
返回false;
返回true;
});
if(existingPerson==null)
重复数据消除PersonList.Add(x);
});
谢谢你的回复,我编辑了我的问题,我在结构中犯了一个大错误,你能再检查一次吗?谢谢你的回复,我编辑了我的问题,我在结构中犯了一个大错误,你能再检查一次吗?你需要更改的一件事是,BaseCode
似乎是Location
的成员,不是人
。这个问题似乎意味着在比较位置时应该忽略基本代码,因此位置比较器
仍然是正确的。@jmh\u gr当我回答时,基本代码
是对的。但是我的实现对BaseCode
没有任何作用,因为需求没有指定如果BaseCode
相等该怎么办。@user783662除了我的示例对象代码之外,解决方案仍然是BaseCode
没有直接使用。你没有指定当BaseCode
相等时如何处理。谢谢你的回复,我编辑了我的问题,我在结构中犯了一个大错误,你能再次检查吗?在这种情况下,locations.equal将不起作用。感谢您的回复,我正在尝试此操作,请您解释一下,并且缺少一个结束括号
class Program
{
static void Main(string[] args)
{
var p1 = new Person {Name ="John", BaseCode="AA12", Locations = new List<Location>
{
new Location { Name = "India" },
new Location { Name = "USA" }
}};
var p2 = new Person {Name ="John", BaseCode="AA13", Locations = new List<Location>
{
new Location { Name = "India" },
new Location { Name = "USA" }
}};
var p3 = new Person {Name ="John", BaseCode="AA14", Locations = new List<Location>
{
new Location { Name = "India" },
new Location { Name = "UK" }
}};
var persons = new List<Person> { p1, p2, p3 };
// Will not return p2.
var distinctPersons = persons.Distinct(new PersonComparer()).ToList();
Console.ReadLine();
}
}
public class PersonComparer : IEqualityComparer<Person>
{
public bool Equals(Person x, Person y)
{
if (x == null || y == null)
return false;
bool samePerson = x.Name == y.Name;
bool sameLocations = !x.Locations
.Except(y.Locations, new LocationComparer())
.Any();
return samePerson && sameLocations;
}
public int GetHashCode(Person obj)
{
return obj.Name.GetHashCode();
}
}
public class LocationComparer : IEqualityComparer<Location>
{
public bool Equals(Location x, Location y)
{
if (x == null || y == null)
return false;
return x.Name == y.Name;
}
public int GetHashCode(Location obj)
{
return obj.Name.GetHashCode();
}
}
public class Person : IEquatable<Person>
{
public string Name { get; set; }
public string BaseCode { get; set; }
public List<Location> Locations { get; set; }
public bool Equals(Person other)
{
if (other == null)
return false;
bool samePerson = Name == other.Name;
// This is simpler because of IEquatable<Location>
bool sameLocations = !Locations.Except(other.Locations).Any();
return samePerson && sameLocations;
}
public override int GetHashCode()
{
return Name.GetHashCode();
}
}
public class Location : IEquatable<Location>
{
public string Name { get; set; }
public bool Equals(Location other)
{
if (other == null)
return false;
return Name == other.Name;
}
public override int GetHashCode()
{
return Name.GetHashCode();
}
}
var distinctPersons = persons.Distinct().ToList();
List<Person> personList = new List<Person>();
List<Person> deduplicatedPersonList = new List<Person>();
personList.ForEach(x =>
{
Person existingPerson = personList.Find(y =>
{
if (y.Locations.Equals(x.Locations))
return false;
return true;
});
if (existingPerson == null)
deduplicatedPersonList.Add(x);
});