C# 将displayname属性作为参数传递

对于以下ActionLink调用：

@Html.ActionLink("Customer Number", "Search", new { Search = ViewBag.Search, q = ViewBag.q, sortOrder = ViewBag.CustomerNoSortParm, })

我正在尝试传入@model.CustomerNumber的标签，以生成“Customer Number”文本，而不必显式传入它。参数是否有@Html.LabelFor（model=>model.CustomerNumber）的等价项

是的，但是很难看

ModelMetadata.FromLambdaExpression(m => m.CustomerNumber, ViewData).DisplayName

---

您可能希望将其包装在扩展方法中。

没有现成的帮助程序

但是编写一个定制的很简单：

public static class HtmlExtensions
{
    public static string DisplayNameFor<TModel, TProperty>(
        this HtmlHelper<TModel> html, 
        Expression<Func<TModel, TProperty>> expression
    )
    {
        var htmlFieldName = ExpressionHelper.GetExpressionText(expression);
        var metadata = ModelMetadata.FromLambdaExpression(expression, html.ViewData);
        return (metadata.DisplayName ?? (metadata.PropertyName ?? htmlFieldName.Split(new[] { '.' }).Last()));
    }
}

---

有一个更简单的答案，伙计们！只需将“[0]”添加到“m=>m.CustomerNumber”即可引用第一行索引值！（是的，即使没有值行，这也会起作用！）

要将其放在您的操作链接中：

@Html.ActionLink(Html.DisplayNameFor(m => m[0].CustomerNumber).ToString(), "Search", new { Search = ViewBag.Search, q = ViewBag.q, sortOrder = ViewBag.CustomerNoSortParm, })

---

小菜一碟

嘿，很老的帖子，但我得到了一个更好更简单的答案：

@Html.ActionLink(Html.DisplayNameFor(x=>x.CustomerName), "Search", new { Search = ViewBag.Search, q = ViewBag.q, sortOrder = ViewBag.CustomerNoSortParm, })

@Html.ActionLink(Html.DisplayNameFor(m => m[0].CustomerNumber).ToString(), "Search", new { Search = ViewBag.Search, q = ViewBag.q, sortOrder = ViewBag.CustomerNoSortParm, })

@Html.ActionLink(Html.DisplayNameFor(x=>x.CustomerName), "Search", new { Search = ViewBag.Search, q = ViewBag.q, sortOrder = ViewBag.CustomerNoSortParm, })