C# 使用Serializable（）从XML文件填写数组

我目前正在尝试使用[Serializable（）]命令对象反序列化XML，但遇到了一些问题。以下是代码示例：

using System;
using System.Xml.Linq;
using System.Xml.Serialization;
using System.IO;

namespace XmlManipulation
{
    public class XmlManip
    {
        public static TestCasesList SerializeTest() //test function
        {
            TestCasesList testslist = null;
            string path = @"C:\Users\sxtx2987\Documents\Visual Studio 2015\Projects\FDB\deleteme\test.xml";

            XmlSerializer serializer = new XmlSerializer(typeof(TestCasesList));

            StreamReader reader = new StreamReader(path);

        testslist = (TestCasesList)serializer.Deserialize(reader);
        reader.Close();
        return testslist;
        }
    }


    [Serializable()]
    public class TestCase
    {
        [System.Xml.Serialization.XmlElement("name")]
        public string name;

        [System.Xml.Serialization.XmlElement("objective")]
        public string objective;

        [System.Xml.Serialization.XmlElement("criteria")]
        public string criteria;

        [System.Xml.Serialization.XmlElement("issue")]
        public string issue;

        [System.Xml.Serialization.XmlElement("clientcomments")]
        public string clientcomments;

        [System.Xml.Serialization.XmlElement("authoritycomments")]
        public string authoritycomments;
    }

    [Serializable()]
    [XmlType("testcaseslist")]
    public class TestCasesList
    {
        [XmlArray("testcase")]
        public TestCase[] TestCase { get; set; }
    }
}

这是我试图反序列化的文件

<xml version="1.00" encoding="UTF-8">
    <campaign>
        <name>Test XML</name>
        <number>XXXXXG04-06-1</number>
        <client>Fictional</client>
        <model>Rocket powered boots</model>
        <authority>Fictional authority</authority>
    </campaign>

    <testcaseslist>
        <testcase>
            <name>TestCase001</name>
            <objective>Objective test 1</objective>
            <criteria>Pass criteria test 1</criteria>
            <issue>Issue Description test 1</issue>
            <clientcomments>Client comments test 1</clientcomments>
            <authoritycomments>Authority comments test 1</authoritycomments>
        </testcase>

        <testcase>
            <name>TestCase002</name>
            <objective>Objective test 2</objective>
            <criteria>Pass criteria test 2</criteria>
            <issue>Issue Description test 2</issue>
            <clientcomments>Client comments test 2</clientcomments>
            <authoritycomments>Authority comments test 2</authoritycomments>
        </testcase>
    </testcaseslist>    
</xml>

我得到一个空的测试对象

我认为我的问题是XmlType和XmlArray部分，但经过几个小时的研究和试验，我仍然无法从XML中获得信息

---

谢谢你抽出时间

这里有一些问题

根元素可能不是您所认为的。您的代码假定

是根元素。但实际上，以下是根本要素：

<xml version="1.00" encoding="UTF-8">
    <!-- XML Contents -->
</xml>

然后，要在XML中向前跳并反序列化

元素，请使用：

你可以做：

    public static TestCasesList Deserialize(TextReader reader)
    {
        var serializer = new XmlSerializer(typeof(XmlRoot));
        var root = (XmlRoot)serializer.Deserialize(reader);
        return root == null ? null : root.testcaseslist;
    }

通过从XML自动生成c#类，可以避免上述一些困难，例如使用。有关更多信息，请参阅

---

顺便说一句，

[Serializable]

对

XmlSerializer

没有影响

谢谢你的详细解释。在搞乱了XML之后，我注意到当我使用这种结构进行序列化时，我可以简单地使用变量名，使用没有[serializable]标记的结构，并简单地使用公共变量进行序列化。不过，您的解释为我解释了XML的机制。非常感谢。

<?xml version="1.0" encoding="UTF-8">

[XmlRoot("testcaseslist")]
public class TestCasesList
{
    [XmlElement("testcase")]
    public TestCase[] TestCase { get; set; }
}

    public static TestCasesList Deserialize(TextReader reader)
    {
        using (var xmlReader = XmlReader.Create(reader))
        {
            // Skip to the <testcaseslist> element.
            if (!xmlReader.ReadToFollowing("testcaseslist", ""))
                return null;

            var serializer = new XmlSerializer(typeof(TestCasesList));
            return (TestCasesList)serializer.Deserialize(xmlReader);
        }
    }

[XmlRoot("xml")]
public class XmlRoot
{
    public TestCasesList testcaseslist { get; set; }
}

    public static TestCasesList Deserialize(TextReader reader)
    {
        var serializer = new XmlSerializer(typeof(XmlRoot));
        var root = (XmlRoot)serializer.Deserialize(reader);
        return root == null ? null : root.testcaseslist;
    }