C# 十进制值的正则表达式

我需要一个正则表达式，它允许.253或任何后跟点的数字

这是我的正则表达式，它允许0.253，但不允许.253

 Regex match = new Regex(@"^[0-9]\d*(\.\d*)?$");

解释

使用这个：

Regex match = new Regex(@"^\d*(?:\.\d+)?$");

---

删除[0-9]后，它将允许您使用.253。类似于^\d*\.？\d+$的问题是：为什么在这里使用正则表达式而不是框架解决方案decimal.TryParse？-请参见@Corak，但我无法限制小数点前后的数字。这就是原因。@m42谢谢你指出这一点，我在用手机，但我想它现在已经修好了。

^[0-9]+?\.?[0-9]+$

Assert position at the beginning of a line (at beginning of the string or after a line break character) «^»
Match a single character present in the list below «[0-9\.]*?»
   Between zero and unlimited times, as few times as possible, expanding as needed (lazy) «*?»
   A character in the range between “0” and “9” «0-9»
   A . character «\.»
Match a single character in the range between “0” and “9” «[0-9]+»
   Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
Assert position at the end of a line (at the end of the string or before a line break character) «$»

Regex match = new Regex(@"^\d*(?:\.\d+)?$");