d3.js组合图线条和散点
我是d3.js的新手,我正在尝试在散点图的顶部添加一条线。我有两个数据集要绘制d3.js组合图线条和散点,d3.js,D3.js,我是d3.js的新手,我正在尝试在散点图的顶部添加一条线。我有两个数据集要绘制 var data = [ { "x" : 30, "y" : 30, "r" : 20, "c" : "green", "s" : "s1" }, { "x" : 70, "y" : 70, "r" : 20, "c" : "purple", "s"
var data = [ {
"x" : 30,
"y" : 30,
"r" : 20,
"c" : "green",
"s" : "s1"
}, {
"x" : 70,
"y" : 70,
"r" : 20,
"c" : "purple",
"s" : "s2"
}, {
"x" : 110,
"y" : 100,
"r" : 20,
"c" : "red",
"s" : "s3"
} ];
var data1 = [{
"x":30,
"y":30},
{"x":70,
"y":70}];
数据变量用作散点序列,在同一图表上,我想将第二个数据集绘制为一个直线序列
var margin = {
top : 20,
right : 20,
bottom : 30,
left : 40
}, width = 960 - margin.left - margin.right, height = 500 - margin.top
- margin.bottom;
var x = d3.scale.linear().range([ 0, width ]);
var y = d3.scale.linear().range([ height, 0 ]);
var color = d3.scale.category10();
var xAxis = d3.svg.axis().scale(x).orient("bottom");
var yAxis = d3.svg.axis().scale(y).orient("left");
var svg = d3.select("#"+div).append("svg").attr("width",
width + margin.left + margin.right).attr("height",
height + margin.top + margin.bottom).append("g").attr(
"transform",
"translate(" + margin.left + "," + margin.top + ")");
var data = [ {
"x" : 30,
"y" : 30,
"r" : 20,
"c" : "green",
"s" : "s1"
}, {
"x" : 70,
"y" : 70,
"r" : 20,
"c" : "purple",
"s" : "s2"
}, {
"x" : 110,
"y" : 100,
"r" : 20,
"c" : "red",
"s" : "s3"
} ];
var data1 = [{
"x":30,
"y":30},
{"x":70,
"y":70}];
x.domain(d3.extent(data, function(d) {
return d.x;
})).nice();
y.domain(d3.extent(data, function(d) {
return d.y;
})).nice();
svg.append("g").attr("class", "x axis").attr("transform",
"translate(0," + height + ")").call(xAxis).append("text").attr(
"class", "label").attr("x", width).attr("y", -6).style(
"text-anchor", "end").text("Yield");
svg.append("g").attr("class", "y axis").call(yAxis).append("text")
.attr("class", "label").attr("transform", "rotate(-90)").attr(
"y", 6).attr("dy", ".71em").style("text-anchor", "end")
.text("Skew")
var line = d3.svg.line()
.x(function(d) { return x(d.x); })
.y(function(d) { return y(d.y); });
svg.selectAll(".line").data(data1).enter().append("path").attr("class","line").attr("d",line);
svg.selectAll(".dot").data(data).enter().append("circle").attr("class",
"dot").attr("r", 3.5).attr("cx", function(d) {
return x(d.x);
}).attr("cy", function(d) {
return y(d.y);
}).style("fill", function(d) {
return color(d.c);
});
var legend = svg.selectAll(".legend").data(color.domain()).enter()
.append("g").attr("class", "legend").attr("transform",
function(d, i) {
return "translate(0," + i * 20 + ")";
});
legend.append("rect").attr("x", width - 18).attr("width", 18).attr(
"height", 18).style("fill", color);
legend.append("text").attr("x", width - 24).attr("y", 9).attr("dy",
".35em").style("text-anchor", "end").text(function(d) {
return d;
});
但我一点也看不出有什么界限 使用数据([data1])(或数据(data1)),并设置行的样式,使其显示:
svg.append("path")
.data([data1])
.attr("class","line")
.attr("stroke", "steelblue")
.attr("fill", "none")
.attr("stroke-width", 1.5)
.attr("d",line);
在以下情况之前:
svg.selectAll(".line").
data(data1).enter()
.append("path")
.attr("class","line")
.attr("d",line);
正在为要打印的每个点创建路径元素
<path class="line"></path>
<path class="line"></path>
而且电话线从来没有人打过。相反,我们需要一个路径对象,并将整个点数组绑定到它。对于该对象,我们使用.attr(“d”,line)添加点,最后得到以下结果:
<path class="line" stroke-width="1.5" d="M0,450L450,192.8571428571429"></path>
请查看mbostock提供的这篇文章(及其链接),了解这篇文章的更多内容。谢谢,现在我可以看到这篇文章了。唯一的问题是,如果我在data1 json数组中再添加一个数据点,它将以一个多边形结束,这条线将连接回数组中的第一个点。是的。这就成功了。虽然我认为它会删除填充并显示多边形。谢谢