Database Laravel DB facade选择动态
我正在尝试在Laravel中使用db facade进行动态选择Database Laravel DB facade选择动态,database,laravel,join,select,laravel-facade,Database,Laravel,Join,Select,Laravel Facade,我正在尝试在Laravel中使用db facade进行动态选择 $EntrepriseSurBAseDuNace = DB::table ('enterpriseAddress') ->join('enterpriseEnterprise', 'enterpriseEnterprise.EnterpriseNumber', '=', 'enterpriseAddress.EntityNumber','LEFT OUTER') ->sel
$EntrepriseSurBAseDuNace = DB::table ('enterpriseAddress')
->join('enterpriseEnterprise', 'enterpriseEnterprise.EnterpriseNumber', '=', 'enterpriseAddress.EntityNumber','LEFT OUTER')
->select('EntityNumber')
->where([
['Zipcode','=',$CodePostal],
['enterpriseEnterprise.StartDate ','=',$DateCreation],
])
->get();
如果数组/变量不是空的,我想添加join,如下所示:
if(isset($Var){
->join ......
}
或
但我不能在请求中这样做。
谢谢你的帮助,对不起我的英语
感谢大卫:
$queryTest = DB::table ('enterpriseAddress');
if (isset($RechercheRequete['CodePostal']))
{
$CodePostal = $RechercheRequete['CodePostal'];
$queryTest->where('enterpriseAddress.Zipcode','=', $CodePostal);
}
$result = $queryTest->select('EntityNumber') ->get(); dd($result);
exit();
我告诉你,进展的结果是什么;)它起作用了,我只是对所有的请求都这样做,这就是为什么需要这么长时间。谢谢你的帮助。事实上,我没有看到没有结果。发生了什么事?你说的“但我不能在请求中这样做”是什么意思?你有什么具体问题?哦,对不起@MichaelKunst,我现在没看到没问题,我不知道如果我的查询中有条件,我该怎么办;)
$queryTest = DB::table ('enterpriseAddress');
if (isset($RechercheRequete['CodePostal']))
{
$CodePostal = $RechercheRequete['CodePostal'];
$queryTest->where('enterpriseAddress.Zipcode','=', $CodePostal);
}
$result = $queryTest->select('EntityNumber') ->get(); dd($result);
exit();
$query = DB::table ('enterpriseAddress');
if (your-condition) {
$query->join(...
} elseif ('other condition') {
$query->join(...
}
$query->select('EntityNumber')
->where([
['Zipcode','=',$CodePostal],
['enterpriseEnterprise.StartDate ','=',$DateCreation],
])->get();