Django 如何重定向到另一个带有搜索词的页面？

我有一个搜索引擎，在主页/视图中运行得非常好。py:

def home(request):
...
form = SearchForm()
query = None
results = []
if 'query' in request.GET:
    form = SearchForm(request.GET)
    if form.is_valid():
        query = form.cleaned_data['query']
        results = products.annotate(
            similarity=TrigramSimilarity('name', query),
        ).filter(similarity__gt=0.15).distinct().order_by('-similarity')
        # return render(request, 'search/search_results.html', locals())
        return redirect(reverse('home:search_results'))
    else:
        form = SearchForm()
...
return render(request, 'home/home.html', context)

def search_results(request):
form = SearchForm()
query = None
results = []
if 'query' in request.GET:
    form = SearchForm(request.GET)
    if form.is_valid():
        query = form.cleaned_data['query']
        results = products.annotate(
            similarity=TrigramSimilarity('name', query),
        ).filter(similarity__gt=0.15).distinct().order_by('-similarity')

        return render(request, 'search/search_results.html', locals())
    else:
        form = SearchForm()

return render(request, 'search/search_results.html', locals())

app_name = 'home'
urlpatterns = [
    path('', views.home, name='home'),
    path('search_results/<query>', views.search_results, name='search_results'),
]\
              + static(settings.STATIC_URL, document_root=settings.STATIC_ROOT) \
              + static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)

我还有inurl.py:

def home(request):
...
form = SearchForm()
query = None
results = []
if 'query' in request.GET:
    form = SearchForm(request.GET)
    if form.is_valid():
        query = form.cleaned_data['query']
        results = products.annotate(
            similarity=TrigramSimilarity('name', query),
        ).filter(similarity__gt=0.15).distinct().order_by('-similarity')
        # return render(request, 'search/search_results.html', locals())
        return redirect(reverse('home:search_results'))
    else:
        form = SearchForm()
...
return render(request, 'home/home.html', context)

def search_results(request):
form = SearchForm()
query = None
results = []
if 'query' in request.GET:
    form = SearchForm(request.GET)
    if form.is_valid():
        query = form.cleaned_data['query']
        results = products.annotate(
            similarity=TrigramSimilarity('name', query),
        ).filter(similarity__gt=0.15).distinct().order_by('-similarity')

        return render(request, 'search/search_results.html', locals())
    else:
        form = SearchForm()

return render(request, 'search/search_results.html', locals())

app_name = 'home'
urlpatterns = [
    path('', views.home, name='home'),
    path('search_results/<query>', views.search_results, name='search_results'),
]\
              + static(settings.STATIC_URL, document_root=settings.STATIC_ROOT) \
              + static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)

app_name='home'
URL模式=[
路径（“”，views.home，name='home'），
路径（'search_results/'，views.search_results，name='search_results'），
]\
+静态（settings.static\u URL，document\u root=settings.static\u root）\
+静态（settings.MEDIA\u URL，document\u root=settings.MEDIA\u root）

如何重定向到具有如下url结构的页面localhost/search\u results/？query=['query']？

尝试以下方法：

return redirect_params(reverse('home:search_results'), {'query': 'query'})

---

这个问题解决了！我尝试应用这样的结构返回重定向（f'/search\u results/？query={query}'）

我不知道这是否是最正确的解决方案，但我得到了我想要的响应localhost/search\u results/？query=umbrary

我希望这对某人有所帮助，如果有人提出更好的解决方案，请写下来。提前谢谢大家

def home(request):
form = SearchForm()
query = None
results = []
if 'query' in request.GET:
    form = SearchForm(request.GET)
    if form.is_valid():
        query = form.cleaned_data['query']
        results = products.annotate(
            similarity=TrigramSimilarity('name', query),
        ).filter(similarity__gt=0.15).distinct().order_by('-similarity')
        return redirect(f'/search_results/?query={query}')
    else:
        form = SearchForm()
return render(request, 'home/home.html', context)

---

未定义名称“重定向参数”。。。django库中没有像redirect_params这样的方法