什么';在Django中,从单个页面处理不同表单的最佳方式是什么?
假设我在视图中定义了3种不同的形式:什么';在Django中,从单个页面处理不同表单的最佳方式是什么?,django,django-forms,Django,Django Forms,假设我在视图中定义了3种不同的形式: # views.py form_one = FormOne() form_two = FormTwo() form_three = FormThree() 在我的模板中: <form action="" method="post" id="form-one"> {{ form_one.as_table }} <input type="submit" value="Submit Form One" name="form-one" /
# views.py
form_one = FormOne()
form_two = FormTwo()
form_three = FormThree()
在我的模板中:
<form action="" method="post" id="form-one">
{{ form_one.as_table }}
<input type="submit" value="Submit Form One" name="form-one" />
</form>
<form action="" method="post" id="form-two">
{{ form_two.as_table }}
<input type="submit" value="Submit Form Two" name="form-two" />
</form>
<form action="" method="post" id="form-three">
{{ form_three.as_table }}
<input type="submit" value="Submit Form Three" name="form-three" />
</form>
有什么意见或建议吗
<form action="?form_id=1" method="post" id="form-one">
url(r'^form1/$', 'someapp.views.process_forms', {'form_class': FormOne}, name='form_one_page'),
url(r'^form2/$', 'someapp.views.process_forms', {'form_class': FormTwo}, name='form_one_page'),
url(r'^form3/$', 'someapp.views.process_forms', {'form_class': FormThree}, name='form_one_page'),
在views.py中:
def process_forms(request, form_class=None):
...
form = form_class(data=request.POST)
...
if request.POST.has_key('form-one'):
...
elif request.POST.has_key('form-two'):
...
elif request.POST.has_key('form-three'):
...
else:
...
我在一个网站上遇到了类似的问题。我现在没有代码,但我想我做了以下几点:
if request.method == 'POST':
valid = False
form = FormOne(request.POST)
if form.is_valid():
#handle case where use submitted FormOne
valid = True
form = FormTwo(request.POST)
if form.is_valid():
#handle case where use submitted FormTwo
valid = True
form = FormThree(request.POST)
if form.is_valid():
#handle case where use submitted FormThree
valid = True
if not valid:
#handle case where none of the forms were valid
处理多个表单的正确方法是在创建表单时使用“prefix”属性。您的视图应该是这样的:
if request.method == 'POST':
form1 = Form1(request.POST, prefix='form1')
form2 = Form2(request.POST, prefix='form2')
form3 = Form3(request.POST, prefix='form3')
if form1.is_valid() and form2.is_valid() and form3.is_valid():
# Do whatever you have to do
pass
else:
form1 = Form1(prefix='form1')
form2 = Form2(prefix='form2')
form3 = Form3(prefix='form3')
模板保持不变,不需要额外的逻辑:
<form ...>
{{ form1.as_table }}
{{ form2.as_table }}
{{ form3.as_table }}
<input type="submit" ... />
</form>
{{form1.as_table}}
{{form2.as_table}}
{{form3.as_table}}
+1。这就是我要做的。这还允许您避免在HTML中使用多个
标记,而改为提交到同一视图。一个可能的更改:第二个和第三个if
分支可以转换为elif
,最后一个if
分支可以变成else
。我在这里看到的唯一问题是,如果每个表单都有类似的表单字段,那么FormOne也可能是validate form2,依此类推。
if request.method == 'POST':
form1 = Form1(request.POST, prefix='form1')
form2 = Form2(request.POST, prefix='form2')
form3 = Form3(request.POST, prefix='form3')
if form1.is_valid() and form2.is_valid() and form3.is_valid():
# Do whatever you have to do
pass
else:
form1 = Form1(prefix='form1')
form2 = Form2(prefix='form2')
form3 = Form3(prefix='form3')
<form ...>
{{ form1.as_table }}
{{ form2.as_table }}
{{ form3.as_table }}
<input type="submit" ... />
</form>