I';我试图在Django模板上输出一个过滤列表

I';我试图在Django模板上输出一个过滤列表,django,Django,例如,我在models.py中有: class Development(models.Model): id = models.AutoField(primary_key=True) client = models.ForeignKey(InsName, on_delete=models.SET_NULL, null=True, blank=True) platform = models.ManyToManyField(Platform) user = models

例如,我在models.py中有:

class Development(models.Model):
    id = models.AutoField(primary_key=True)
    client = models.ForeignKey(InsName, on_delete=models.SET_NULL, null=True, blank=True)
    platform = models.ManyToManyField(Platform)
    user = models.ForeignKey(User, on_delete=models.CASCADE)
在views.py中(将相应的url添加到url.py中):


如何告诉我的模板只输出特定客户机的数据库条目列表?

您需要在视图类中定义一个
get\u queryset
函数,该函数返回开发模型的queryset。像这样的方法应该会奏效:

def get_queryset(self):
    return Development.objects.filter(client__id=1)

必须使用get_queryset from ListView类的方法,如下所示:

class DevelopmentFilterView(generic.ListView):
    model = Development
    queryset = Development.objects.all()

    def get_queryset(self):
       qs = super().get_queryset()
       qs = qs.filter(client=client)
       return qs
class DevelopmentFilterView(generic.ListView):
    model = Development
    queryset = Development.objects.all()

    def get_queryset(self):
       qs = super().get_queryset()
       qs = qs.filter(client=client)
       return qs