Drools 如何在drool规则引擎中处理列表项中对象的上一个值?
我想在列表中的所有元素中都使用Drool to fire规则 这是我的订单 DroolTest.java 输出 如您所见,then条件只执行一次,因为 当流口水时,检查11>10,这工作正常,并将值设置为 0但当drools处理第二个列表项时,现在总和将返回0+7> 10这是错误的,但我想在第二个列表中激活条件 因为11+7=19大于10,有没有办法开火 那么这两个列表项的条件是什么?我们有没有办法拿到那张票 对象的原始值不是来自工作记忆Drools 如何在drool规则引擎中处理列表项中对象的上一个值?,drools,rule,business-rules,Drools,Rule,Business Rules,我想在列表中的所有元素中都使用Drool to fire规则 这是我的订单 DroolTest.java 输出 如您所见,then条件只执行一次,因为 当流口水时,检查11>10,这工作正常,并将值设置为 0但当drools处理第二个列表项时,现在总和将返回0+7> 10这是错误的,但我想在第二个列表中激活条件 因为11+7=19大于10,有没有办法开火 那么这两个列表项的条件是什么?我们有没有办法拿到那张票 对象的原始值不是来自工作记忆 您添加了一个模式OrderItem,以便规则将为超过限制
您添加了一个模式OrderItem,以便规则将为超过限制的订单的每个项目激发
rule "order"
when
$order: Order( $code: code )
accumulate( OrderItem( order == $order, $price: price,
code == $code );
$total: sum( $price );
$total > Order.ORDER_AMOUNT_LIMIT )
$item: OrderItem( order == $order, $price: price, code == $code )
then
System.out.println( $item ); // an order item of a "big" order
end
package com.sample;
import java.util.ArrayList;
import java.util.List;
public class OrderItem {
public static final int TEMP_PRICE = 0;
public Order order;
public int price;
public String code;
public List<String> message=new ArrayList();
public void addMessage(String msg){
message.add(msg);
}
public String getCode() {
return code;
}
public void setCode(String code) {
this.code = code;
}
OrderItem(Order order,int price){
this.order = order;
this.price = price;
}
public Order getOrder() {
return order;
}
public void setOrder(Order order) {
this.order = order;
}
public int getPrice() {
return price;
}
public void setPrice(int price) {
this.price = price;
}
}
package com.sample
import com.sample.Order;
rule "order"
when
$order : Order()
$total : Double() from accumulate( OrderItem( order == $order, $price : price,code == $order.code,),
sum( $price ) )
eval($total>Order.ORDER_AMOUNT_LIMIT)
then
System.out.println($total);
$order.orderItems.get(0).price=0;
System.out.println("price is "+ $order.orderItems.get(0).getPrice());
end
public class DroolsTest {
public static final void main(String[] args) {
try {
// load up the knowledge base
KieServices ks = KieServices.Factory.get();
KieContainer kContainer = ks.getKieClasspathContainer();
KieSession kSession = kContainer.newKieSession("ksession-rules");
Order order = new Order(1,"bob");
order.setCode("test1");
OrderItem item1 = new OrderItem(order, 11);
item1.setCode("test1");
OrderItem item2 = new OrderItem(order, 7);
item2.setCode("test1");
order.addOrderItem(item1);
order.addOrderItem( item2 );
kSession.insert(order);
kSession.insert(item1);
kSession.fireAllRules();
kSession.insert(item2);
kSession.fireAllRules();
} catch (Throwable t) {
t.printStackTrace();
}
}
}
11.0
price is 0
rule "order"
when
$order: Order( $code: code )
accumulate( OrderItem( order == $order, $price: price,
code == $code );
$total: sum( $price );
$total > Order.ORDER_AMOUNT_LIMIT )
$item: OrderItem( order == $order, $price: price, code == $code )
then
System.out.println( $item ); // an order item of a "big" order
end