Drop down menu 如何在php中从下拉列表中删除帖子
我有一个用下拉列表删除帖子的表单。但删除不起作用, 它被删除了,但当我去看一看,它不工作。有什么想法吗 index.phpDrop down menu 如何在php中从下拉列表中删除帖子,drop-down-menu,sql-delete,Drop Down Menu,Sql Delete,我有一个用下拉列表删除帖子的表单。但删除不起作用, 它被删除了,但当我去看一看,它不工作。有什么想法吗 index.php $delete = $_POST['delete_submit']; mysql_query("DELETE FROM posts WHERE Post_id=$delete"); ?> <section style="font-size: 22px; text-align: center;"> <form action=
$delete = $_POST['delete_submit'];
mysql_query("DELETE FROM posts WHERE Post_id=$delete");
?>
<section style="font-size: 22px; text-align: center;">
<form action='check.php' method='post' onsubmit="return confirm('Do you really want to
delete this post?');">
<p>
Delete Post:
<select name="delete">
<option>Please select a post</option>
<?php
$result = mysql_query("SELECT Post_id, Post_title FROM posts ORDER BY Post_id
DESC");
while ($row = mysql_fetch_array($result)){
$blogvar = array($row ['Post_id'], $row ['Post_title']);
?>
<option><?php echo $blogvar[1]; ?></option>
<?php
}
?>
</select>
<p></p>
<input type='submit' class='button' name='submit' value='Delete'/>
</p>
</form>
</section>
谢谢这里有太多错误,但无论如何
check.php
文件中的SQL实际上应该删除所有帖子,因为您正在将post\u id
字段与SQL中的自身进行比较delete
,因此应该是$\u POST['delete']
——但请继续阅读,您的错误不会到此为止delete
的元素将屏蔽第一个元素,这意味着无论您选择$\u POST['delete']
的值是什么,您都需要更改其中一个名称
s没有任何值
属性,这意味着您的post\u id
实际上没有作为delete
select元素的值提交请提供一些代码,您尝试了什么?问题仍然存在。我能做什么?我再次更新了我的答案,应该是#5非常感谢,先生,现在它正在工作
include "base.php";
mysql_query("DELETE FROM posts WHERE post_id =$_POST['delete']")