Elixir “长生不老药”;case子句错误“;而模式匹配HTTPoison响应
我正在使用Httpoison执行一个get请求,并希望使用case语句对响应进行模式匹配。代码如下:Elixir “长生不老药”;case子句错误“;而模式匹配HTTPoison响应,elixir,phoenix-framework,httpoison,Elixir,Phoenix Framework,Httpoison,我正在使用Httpoison执行一个get请求,并希望使用case语句对响应进行模式匹配。代码如下: def current() do case HTTPoison.get!(@api_url) do {:ok, %HTTPoison.Response{body: body, status_code: 200}} -> IO.puts body {:error, %HTTPoison.Error{reason: reason}} ->
def current() do
case HTTPoison.get!(@api_url) do
{:ok, %HTTPoison.Response{body: body, status_code: 200}} ->
IO.puts body
{:error, %HTTPoison.Error{reason: reason}} ->
IO.inspect reason
end
end
当状态代码为200时,打印正文。
出现错误时,检查原因
我从服务器上得到这样的响应
%HTTPoison.Response{body: "{\"USD\":10067.08}", headers: <<removed for readability>>, status_code: 200}
%HTTPoison.Response{body:{\'USD\':10067.08},标题:,状态\代码:200}
以及,(CaseClauseError)无case子句匹配的错误:
当我收到一个正文和状态代码为200的响应时,为什么会出现“no子句”错误?问题在于
代码>在获取之后
HTTPoison.get!(@api_url)
将返回%HTTPoison.Response{body:body,…}
或引发异常
如果您想要{:ok,%HTTPoison.Response{body:body,…}
,请使用HTTPoison.get(@api\u url)
(不带!
)
或者:
def current() do
case HTTPoison.get(@api_url) do
{:ok, %HTTPoison.Response{body: body, status_code: 200}} ->
IO.puts body
{:error, %HTTPoison.Error{reason: reason}} ->
IO.inspect reason
end
end
或
def current() do
%HTTPoison.Response{body: body, status_code: 200}} = HTTPoison.get!(@api_url)
IO.puts body
end