Email hotmail未接收图像附件内容
我正在尝试使用PHP通过Amazons发送带有图像附件的原始电子邮件。当我将电子邮件发送到gmail帐户时效果很好,但是hotmail帐户收到的是空的附加图像。换句话说,hotmail似乎认识到存在附件,并且这些附件具有我指定的正确名称,只是它们总是空的,大小为0字节。谷歌搜索没有帮助。。。提前谢谢Email hotmail未接收图像附件内容,email,attachment,mime,hotmail,Email,Attachment,Mime,Hotmail,我正在尝试使用PHP通过Amazons发送带有图像附件的原始电子邮件。当我将电子邮件发送到gmail帐户时效果很好,但是hotmail帐户收到的是空的附加图像。换句话说,hotmail似乎认识到存在附件,并且这些附件具有我指定的正确名称,只是它们总是空的,大小为0字节。谷歌搜索没有帮助。。。提前谢谢 $amazonSES = new AmazonSES(); // if (empty($attach)==0) { // $response = $amazonSES->send_e
$amazonSES = new AmazonSES();
// if (empty($attach)==0) {
// $response = $amazonSES->send_email(AWS_SES_FROM_EMAIL,
// array('ToAddresses' => array($to)),
// array('Subject.Data' => $subject,'Body.Text.Data' => $messagein,)
// );
// } else {
$rstring = 'ajfas90lsjhntlen89y34oi598';
$message= "To: ".$to."\n";
$message.= "From: " . AWS_SES_FROM_EMAIL . "\n";
$message.= "Subject: " . $subject . "\n";
$message.= "MIME-Version: 1.0\n";
$message.= 'Content-Type: multipart/mixed; boundary="ARandomString'.$rstring.'"';
$message.= "\n\n";
$message.= "--ARandomString$rstring\n";
$message.= 'Content-Type: text/plain; charset="utf-8"';
$message.= "\n";
$message.= "Content-Transfer-Encoding: 7bit\n";
$message.= "Content-Disposition: inline\n";
$message.= "\n";
$message.= $messagein;
$message.= "\n\n";
$message.= "--ARandomString$rstring\n";
foreach ($attach as $attachment) {
// $message.= "Content-ID: \<77987_SOME_WEIRD_TOKEN_BUT_UNIQUE_SO_SOMETIMES_A_@domain.com_IS_ADDED\>\n";
$message.= "Content-ID: \<". md5(uniqid(rand(), true)) ."@biomechanico.com\>\n";
$message.= 'Content-Type: application/zip; name="shell.zip"';
$message.= "\n";
$message.= "Content-Transfer-Encoding: base64\n";
$message.= 'Content-Disposition: attachment; filename="' . $attachment["name"] . '"';
$message.= "\n" . base64_encode(file_get_contents($attachment["file"])) . "\n";
$message.= "--ARandomString$rstring\n";
}
$response = $amazonSES->send_raw_email(array(
'Data'=> base64_encode($message)),
array('Source'=>AWS_SES_FROM_EMAIL, 'Destinations'=> $to));
$amazonSES=新amazonSES();
//如果(空($attach)=0){
//$response=$amazonSES->send_email(AWS_SES_FROM_email,
//数组('toaddress'=>array($to)),
//数组('Subject.Data'=>$Subject,'Body.Text.Data'=>$messagein,)
// );
//}其他{
$rstring='ajfas90lsjhntlen89y34oi598';
$message=“To:”.$To.“\n”;
$message.=“发件人:”.AWS\u SES\u From\u EMAIL.“\n”;
$message.=“主题:”.$Subject.\n”;
$message.=“MIME版本:1.0\n”;
$message.='Content Type:multipart/mixed;boundary=“ARandomString”。$rstring.'”;
$message.=“\n\n”;
$message.=“--ARandomString$rstring\n”;
$message.=“内容类型:text/plain;charset=“utf-8”;
$message.=“\n”;
$message.=“内容传输编码:7bit\n”;
$message.=“内容配置:内联\n”;
$message.=“\n”;
$message.=$messagein;
$message.=“\n\n”;
$message.=“--ARandomString$rstring\n”;
foreach($attached as$attachment){
//$message.=“内容ID:\\n”;
$message.=“内容ID:\\n”;
$message.=“内容类型:application/zip;name=“shell.zip””;
$message.=“\n”;
$message.=“内容传输编码:base64\n”;
$message.='Content-Disposition:attachment;filename=“”。$attachment[“name”].';
$message.=“\n”.base64\u编码(文件获取内容($attachment[“file”])。“\n”;
$message.=“--ARandomString$rstring\n”;
}
$response=$amazonSES->send_raw_email(数组)(
“数据”=>base64_编码($message)),
数组('Source'=>AWS_SES_FROM_EMAIL,'Destinations'=>$to));
您正在生成格式不正确的消息
考虑使用适当的库来生成邮件消息,而不是从原始字符串将它们缝合在一起
否则,我马上就会注意到
--
终止,即最后一行必须是:
--ARandomStringajfas90lsjhntlen89y34oi598--
而不是
-ARandomStringajfas90lsjhntlen89y34oi598
内容处置
标题行和正文之间没有空行内容ID
的语法是错误的,因为它产生内容ID:\
,但应该产生内容ID:
\r\n
)终止,但您有LF(\n
)$message
)并运行它。如果上述建议没有帮助,请发布生成的消息源,而不是PHP代码
有关Internet邮件格式,请参阅。有关多部分邮件语法,请参阅。这些解决了我的问题。谢谢。我尝试使用PHPmailer,但不知道如何使其与Amazons一起工作。谢谢again@nbunderson您可能需要调用类似的函数,并将结果字符串分配给
$message
。