Excel formula 我需要列名称中的公式“；二月“；

我有一组数据如下

第1页

                +------+-------+
                |    JANUARY   |
                +------+-------+
+----+----------+------+-------+
| ID | NAME     |COUNT | PRICE |
+----+----------+------+-------+
| 1  |  ALFRED  |  11  |  150  |
| 2  |  ARIS    |  22  |  120  |
| 3  |  JOHN    |  33  |  170  |
| 4  |  CHRIS   |  22  |  190  |
| 5  |  JOE     |  55  |  120  |
| 6  |  ACE     |  11  |  200  |
+----+----------+------+-------+

第2张

+----+----------+------+-------+
| ID | NAME     |COUNT | PRICE |
+----+----------+------+-------+
| 1  |  CHRIS   |  13  |  123  |
| 2  |  ACE     |  26  |  165  |
| 3  |  JOE     |  39  |  178  |
| 4  |  ALFRED  |  21  |  198  |
| 5  |  JOHN    |  58  |  112  |
| 6  |  ARIS    |  11  |  200  |
+----+----------+------+-------+

结果应如表1所示：

                +------+-------++------+-------+
                |    JANUARY   |   FEBRUARY    |
                +------+-------++------+-------+
+----+----------+------+-------++-------+-------+
| ID | NAME     |COUNT | PRICE || COUNT | PRICE |
+----+----------+------+-------++-------+-------+
| 1  |  ALFRED  |  11  |  150  ||  21   |  198  |       
| 2  |  ARIS    |  22  |  120  ||  11   |  200  |       
| 3  |  JOHN    |  33  |  170  ||  58   |  112  |       
| 4  |  CHRIS   |  22  |  190  ||  13   |  123  |       
| 5  |  JOE     |  55  |  120  ||  39   |  178  |       
| 6  |  ACE     |  11  |  200  ||  26   |  165  |         
+----+----------+------+-------++-------+-------+

我需要列名为“二月”的公式。此公式将在表2中找到匹配项

SELECT T2.ID_ENTRY, T1.TAG, T1.TAG2, T2.Name, T2.LastName, T2.Age, T2.Tel
FROM Table1 T1
INNER JOIN Table2 T2
ON T1.ID = T2.ID
GROUP BY T2.ID_ENTRY, T1.TAG, T1.TAG2, T2.Name, T2.LastName, T2.Age, T2.Tel
HAVING Count(T2.ID_ENTRY) > 1

---

构建样本数据

create table table1(
    id int,
    id_entry varchar(10),
    tag int,
    tag2 int
)
create table table2(
    id int,
    name varchar(50),
    lastname varchar(50),
    age int,
    tel int
)
insert into table1
select 1, 'A1', 11, 12 union all
select 2, 'C2', 22, 13 union all
select 3, 'S5', 33, 14 union all
select 4, 'C2', 22, 13 union all
select 5, 'B6', 55, 16 union all
select 6, 'A1', 11, 12

insert into table2
select 1, 'ALFRED', 'DAVE', 21, 555 union all
select 2, 'FRED', 'SMITH', 22, 666 union all
select 3, 'MANNY', 'PAC', 23, 777 union all
select 4, 'FRED', 'DAVE', 22, 666 union all
select 5, 'JOHN', 'SMITH', 25, 999 union all
select 6, 'ALFRED', 'DAVE', 21, 555

drop table table1
drop table table2

解决方案

;with cte as(
    select
        t1.id_entry,
        t1.tag,
        t1.tag2,
        t2.name,
        t2.lastname,
        t2.age,
        t2.tel,
        cc = count(*) over(partition by t1.id_entry),
        rn = row_number() over(partition by t1.id_entry order by t2.lastname desc)
    from table1 t1
    inner join table2 t2
        on t2.id = t1.id
)
select
    id_entry,
    tag,
    tag2,
    name,
    lastname,
    age,
    tel
from cte
where 
    cc > 1
    and rn = 1

丢弃样本数据

create table table1(
    id int,
    id_entry varchar(10),
    tag int,
    tag2 int
)
create table table2(
    id int,
    name varchar(50),
    lastname varchar(50),
    age int,
    tel int
)
insert into table1
select 1, 'A1', 11, 12 union all
select 2, 'C2', 22, 13 union all
select 3, 'S5', 33, 14 union all
select 4, 'C2', 22, 13 union all
select 5, 'B6', 55, 16 union all
select 6, 'A1', 11, 12

insert into table2
select 1, 'ALFRED', 'DAVE', 21, 555 union all
select 2, 'FRED', 'SMITH', 22, 666 union all
select 3, 'MANNY', 'PAC', 23, 777 union all
select 4, 'FRED', 'DAVE', 22, 666 union all
select 5, 'JOHN', 'SMITH', 25, 999 union all
select 6, 'ALFRED', 'DAVE', 21, 555

drop table table1
drop table table2

---

列“Table2.ID_ENTRY”在选择列表中无效，因为它未包含在聚合函数或GROUP BY子句中。-有这个错误吗？你有没有检查过它是否在组中，就像上面我的答案所示？我确实有一个小的语法错误-现在已修复。谢谢，我得到了它。还有一个问题，可以计算2个字段，例如count（T2.Name&T2.LastName），但不完全可以使用count（T2.Name）作为T2NameCount，count（T2.LastName）作为T2LastNameCount，等等。。