Excel 用于存储和统计唯一ID出现次数的多维数组
背景:Excel 用于存储和统计唯一ID出现次数的多维数组,excel,vba,Excel,Vba,背景: Option Explicit Private Sub unique_arr() Dim arr As Variant, i As Long, lr As Long, k As Long lr = Cells(Rows.Count, 1).End(xlUp).Row ReDim arr(2, k) For i = 1 To lr If Application.IfError(Application.Match(Cells(i, 1).Va
Option Explicit
Private Sub unique_arr()
Dim arr As Variant, i As Long, lr As Long, k As Long
lr = Cells(Rows.Count, 1).End(xlUp).Row
ReDim arr(2, k)
For i = 1 To lr
If Application.IfError(Application.Match(Cells(i, 1).Value, arr, 0), 0) = 0 Then
ReDim Preserve arr(2, 0 To k)
arr(1, k) = Cells(i, 1).Value
arr(2, k) = 1
k = k + 1
Else
arr(2, Application.Match(Cells(i, 1), arr(1), 0)) = arr(2, Application.Match(Cells(i, 1), arr(1), 0)) + 1
End If
Next i
For i = LBound(arr) To UBound(arr)
Cells(i + 1, 3).Value = arr(1, i)
Cells(i + 1, 4).Value = arr(2, i)
Next i
End Sub
为了更好地理解动态多维数组,我尝试构建一个数组来捕获唯一值并计算唯一值的出现次数(我应该能够用countif快速验证这一点)
在阅读有关尝试重拨保留多维数组的内容时,我了解到您只能重拨最后一个参数,因此我尝试设置两个参数,其中第一个是唯一值,第二个是计数:arr(2,k)。如果我的理解是错误的,那么这也是非常重要的
我将数组的最终输出放入第3列(唯一ID)和第4列(出现次数)
问题:
Option Explicit
Private Sub unique_arr()
Dim arr As Variant, i As Long, lr As Long, k As Long
lr = Cells(Rows.Count, 1).End(xlUp).Row
ReDim arr(2, k)
For i = 1 To lr
If Application.IfError(Application.Match(Cells(i, 1).Value, arr, 0), 0) = 0 Then
ReDim Preserve arr(2, 0 To k)
arr(1, k) = Cells(i, 1).Value
arr(2, k) = 1
k = k + 1
Else
arr(2, Application.Match(Cells(i, 1), arr(1), 0)) = arr(2, Application.Match(Cells(i, 1), arr(1), 0)) + 1
End If
Next i
For i = LBound(arr) To UBound(arr)
Cells(i + 1, 3).Value = arr(1, i)
Cells(i + 1, 4).Value = arr(2, i)
Next i
End Sub
向数组添加值时,我无法收集所有唯一值。我已经能够收集到3个唯一的值,当数据中有6个时,每个值的出现次数都保持在1,例如,不迭代
问题:
Option Explicit
Private Sub unique_arr()
Dim arr As Variant, i As Long, lr As Long, k As Long
lr = Cells(Rows.Count, 1).End(xlUp).Row
ReDim arr(2, k)
For i = 1 To lr
If Application.IfError(Application.Match(Cells(i, 1).Value, arr, 0), 0) = 0 Then
ReDim Preserve arr(2, 0 To k)
arr(1, k) = Cells(i, 1).Value
arr(2, k) = 1
k = k + 1
Else
arr(2, Application.Match(Cells(i, 1), arr(1), 0)) = arr(2, Application.Match(Cells(i, 1), arr(1), 0)) + 1
End If
Next i
For i = LBound(arr) To UBound(arr)
Cells(i + 1, 3).Value = arr(1, i)
Cells(i + 1, 4).Value = arr(2, i)
Next i
End Sub
很抱歉,这基本上是两个问题
- 1) 我使用的redim保存器arr(2,0到k)语法是否合适
- 2) 我的动态数组生成是否有一个突出的问题,可以解释为什么我没有捕获所有的唯一值
数据的外观:
Option Explicit
Private Sub unique_arr()
Dim arr As Variant, i As Long, lr As Long, k As Long
lr = Cells(Rows.Count, 1).End(xlUp).Row
ReDim arr(2, k)
For i = 1 To lr
If Application.IfError(Application.Match(Cells(i, 1).Value, arr, 0), 0) = 0 Then
ReDim Preserve arr(2, 0 To k)
arr(1, k) = Cells(i, 1).Value
arr(2, k) = 1
k = k + 1
Else
arr(2, Application.Match(Cells(i, 1), arr(1), 0)) = arr(2, Application.Match(Cells(i, 1), arr(1), 0)) + 1
End If
Next i
For i = LBound(arr) To UBound(arr)
Cells(i + 1, 3).Value = arr(1, i)
Cells(i + 1, 4).Value = arr(2, i)
Next i
End Sub
所有数据都在A列中
cat
dog
mouse
cat
mouse
bear
frog
cat
moose
cat
dog
问题代码:
Option Explicit
Private Sub unique_arr()
Dim arr As Variant, i As Long, lr As Long, k As Long
lr = Cells(Rows.Count, 1).End(xlUp).Row
ReDim arr(2, k)
For i = 1 To lr
If Application.IfError(Application.Match(Cells(i, 1).Value, arr, 0), 0) = 0 Then
ReDim Preserve arr(2, 0 To k)
arr(1, k) = Cells(i, 1).Value
arr(2, k) = 1
k = k + 1
Else
arr(2, Application.Match(Cells(i, 1), arr(1), 0)) = arr(2, Application.Match(Cells(i, 1), arr(1), 0)) + 1
End If
Next i
For i = LBound(arr) To UBound(arr)
Cells(i + 1, 3).Value = arr(1, i)
Cells(i + 1, 4).Value = arr(2, i)
Next i
End Sub
虽然使用字典总体上会更好,但If比较有一些错误
If Application.IfError(Application.Match(Cells(i, 1).Value, arr, 0), 0) = 0 Then
VBA有自己的IsError,它返回True/False
If IsError(Application.Match(Cells(i, 1).Value, arr, 0), 0)) Then
此外,arr是一个二维阵列;本质上,它既有行也有列。工作表的匹配只能在一列或一行上使用。你需要用索引“切掉”你想要的东西
If Not IsError(Application.Match(Cells(i, 1).Value, application.index(arr, 1, 0), 0), 0)) Then
最后,arr被定义为ReDim-arr(2,k)
。这使得它arr(0到2,0到k)
因此第一级有三个元素(0,1,2),而不是2。实际上,您从未在第一列中使用0。应该是,
k = 1
ReDim arr(1 to 2, 1 to k)
一切都结束了,你会有这样的结局
Option Explicit
Private Sub unique_arr()
Dim i As Long, lr As Long, k As Long, arr As Variant, m As Variant
'assign values to some vars
lr = Cells(Rows.Count, 1).End(xlUp).Row
k = 1
ReDim arr(1 To 2, 1 To k)
'loop through cells, finding duplicates and counting
For i = 1 To lr
m = Application.Match(Cells(i, 1).Value, Application.Index(arr, 1, 0), 0)
If IsError(m) Then
ReDim Preserve arr(1 To 2, 1 To k)
arr(1, k) = Cells(i, 1).Value
arr(2, k) = 1
k = k + 1
Else
arr(2, m) = arr(2, m) + 1
End If
Next i
'loop through array's second rank
For i = LBound(arr, 2) To UBound(arr, 2)
Cells(i, 3).Value = arr(1, i)
Cells(i, 4).Value = arr(2, i)
Next i
End Sub
对于这样的事情,我会使用字典,比如:
Sub ExtractUniqueCounts()
Dim ws As Worksheet
Dim rCell As Range
Dim hUnq As Object
Set ws = ActiveWorkbook.ActiveSheet
Set hUnq = CreateObject("Scripting.Dictionary") 'Create Dictionary object
'Loop through populated cells in column A
For Each rCell In ws.Range("A1", ws.Cells(ws.Rows.Count, "A").End(xlUp)).Cells
'Ignore blanks
If Len(rCell.Value) > 0 Then
'Check if this is a new, unique value that hasn't been added yet
If Not hUnq.Exists(rCell.Value) Then
'New unique value found, add to dictionary and set count to 1
hUnq(rCell.Value) = 1
Else
'Not a unique value, increase existing count
hUnq(rCell.Value) = hUnq(rCell.Value) + 1
End If
End If
Next rCell
'Check if there are any results
If hUnq.Count > 0 Then
'Results found
'Output the keys (unique values)
ws.Range("C1").Resize(hUnq.Count).Value = Application.Transpose(hUnq.keys)
'Output the values of the keys (the counts in this case)
ws.Range("D1").Resize(hUnq.Count).Value = Application.Transpose(hUnq.items)
Else
'No results, return error
MsgBox "No data"
End If
End Sub
…事后来看,我可以对上述数据使用Match()并仅在找到它时添加,例如application.Match(单元格(I,1).value,range(单元格(1,1),单元格(I-1,1)),0)。。。但是需要从第2行开始以避免错误。这必须是VBA吗?pivot表可以快速轻松地完成此操作。@tigeravatar这纯粹是为了帮助理解如何通过(相对)简单的过程引用/使用多维数组。我知道有更简单的方法来执行这项特定任务,但可以说,我觉得这是一种能让我获得最大回报的方法。这是一种很好的方法,并解释了如何按照OP的要求使用阵列、+1新贡献者和提供良好书面说明?!你真是独角兽(不要和尤尼奇·霍恩混淆)。我很欣赏关于在第一维度中不使用0的解释;这是使这项工作发挥作用的关键。另外,我很抱歉对application.iferror()懒惰。。。我发现自己经常忽略if语句的boolean用法感谢字典的使用。我很感谢大家对这一点的评论,因为我知道dictionary也可以执行这一特定任务。我非常努力地理解设置和动态增加多维数组的适当用法,并试图将我的理解向前推进。我要说的是,我从中得到的最大收获是使用转置输出数据。这是一个巨大的节省时间!关于字典的另一课。现在我将数组视为一个工作表,但字典只是前两行(因此转置),尽管对于唯一值来说,速度非常快。