ExtJS setTimeout调用函数，但在销毁视图后，我收到一些错误

我有一个函数，3000秒后调用其他函数检查网格的新数据

onViewDestroy: function(view) {
        console.log('view destroy');
        var me = this;
        if(me.timer) clearTimeout(me.timer);
    },
    afterRender: function(){

     // start timer to load log grid in 3 secs
         me.logTimer = setTimeout(Ext.bind(me.checkProcessLog, me), 3000);

    },    
    checkProcessLog: function() {
                console.log('check process log');

                var me = this,
                   requestGrid = me.getRequestGrid(),
                   logGrid = me.getProcessLog(),
                   logStore = logGrid.getStore();

                var selectedRecord = requestGrid.getSelectionModel().getSelection()[0];

                // if the grid is expanded and the status of the process is pending or in progress
                if (!logGrid.collapsed && (selectedRecord.get('Status') == 0 || selectedRecord.get('Status') == 1)) {

                    logStore.load({
                        callback: function(records, op, success) {

                            if (success) {

                                // start timer to load again log grid in 3 secs
                                me.logTimer = setTimeout(Ext.bind(me.checkProcessLog, me), 3000);

                            }

                        }
                    });

                }

            },

我遇到的问题是，如果在调用函数时关闭视图（销毁），则所有变量如下：

  requestGrid = me.getRequestGrid(),
    logGrid = me.getProcessLog(),
    logStore = logGrid.getStore();

我得到一个错误：

无法读取未定义的属性“getStore”

---

这是有道理的，因为视图已被破坏。任何避免这种情况的解决方法？

只需简单检查即可：

requestGrid = me.getRequestGrid(),
logGrid = me.getProcessLog();
if(!logGrid) return false
logStore = logGrid.getStore();

这也将停止调用函数