Firebase 无法登录或登录时，将作为消息显示给用户的PlatformException

我需要设置一个警报消息，如果登录失败-提供最准确的根本原因失败给用户

为了确保涵盖所有可能性，我在提交内容中有不同级别的警报

我面临的问题是，此警报无法识别PlatformException

errorMessage返回空值

无论我测试的是什么问题，例如错误代码、现有电子邮件等，我都找不到导致出现未定义问题的原因

---

您应该将

catch

块中的错误传递给

AuthExceptionHandler.generateeExceptionMessage（）

并从那里显示给用户。

Exception has occurred.
PlatformException (PlatformException(ERROR_EMAIL_ALREADY_IN_USE, The email address is already in use by another account., null))

  void _submitForm() {
    if (!_formKey.currentState.validate()) {
      return;
    }

    _formKey.currentState.save();
    try{
    AuthNotifier authNotifier = Provider.of<AuthNotifier>(context, listen: false);
    final status = login(_user, authNotifier);
    if (_authMode == AuthMode.Login) {
      login(_user, authNotifier);
      print("Signed In with ID");
    } else {
      signup(_user, authNotifier);
    } if (status == AuthResultStatus.successful) {
    } else {
        final errorMsg = AuthExceptionHandler.generateExceptionMessage(status);
        _showAlertDialog(errorMsg);
      }
      return;
    } catch (e) {
        print(e);
        setState(() {
          _warning = e.message;
        });
      }
  }

_showAlertDialog(errorMsg) {
    return showDialog(
        context: context,
        builder: (context) {
          return AlertDialog(
            title: Text(
              'Login Failed',
              style: TextStyle(color: Colors.black),
            ),
            content: Text(errorMsg),
          );
        });
  }

class AuthExceptionHandler {
  static handleException(e) {
    print(e.code);
    var status;
    switch (e.code) {
      case "ERROR_INVALID_EMAIL":
        status = AuthResultStatus.invalidEmail;
        break;
      case "ERROR_WRONG_PASSWORD":
        status = AuthResultStatus.wrongPassword;
        break;
      case "ERROR_USER_NOT_FOUND":
        status = AuthResultStatus.userNotFound;
        break;
      case "ERROR_USER_DISABLED":
        status = AuthResultStatus.userDisabled;
        break;
      case "ERROR_TOO_MANY_REQUESTS":
        status = AuthResultStatus.tooManyRequests;
        break;
      case "ERROR_OPERATION_NOT_ALLOWED":
        status = AuthResultStatus.operationNotAllowed;
        break;
      case "ERROR_EMAIL_ALREADY_IN_USE":
        status = AuthResultStatus.emailAlreadyExists;
        break;
      default:
        status = AuthResultStatus.undefined;
    }
    return status;