Flutter 来自服务器响应的颤振返回数组

在我的代码的这一部分

等待webApi.getKeywords（）返回可以从服务器获取的数组，现在当我尝试返回时，我得到错误：

type 'List<dynamic>' is not a subtype of type 'String'

返回
响应。正文
：

[
  {
    "id": 1,
    "user_id": 1,
    "title": "asdasdasd",
    "description": "asdasdasd",
    "type": "post",
    "slug": "asdasdad",
    "featured_images": {
      "images": {
        "300": "/uploads/post_images/2019/300_1573573784.png",
        "600": "/uploads/post_images/2019/600_1573573784.png",
        "900": "/uploads/post_images/2019/900_1573573784.png",
        "original": "/uploads/post_images/2019/1573573784.png"
      },
      "thumbnail": "/uploads/post_images/2019/300_1573573784.png"
    },
    "lang": "fa",
    "visit": 0,
    "categories": [
      {
        "id": 1,
        "title": "aaaaaaa",
        "lang": "fa",
        "parent": 0,
        "pivot": {
          "contents_id": 1,
          "content_categories_id": 1
        }
      }
    ]
  },
  {
    "id": 2,
    "user_id": 1,
    "title": "asdasdasd",
    "description": "asdadasd",
    "type": "post",
    "slug": "asdasdasda",
    "featured_images": {
      "images": {
        "300": "/uploads/post_images/2019/300_1573573846.png",
        "600": "/uploads/post_images/2019/600_1573573846.png",
        "900": "/uploads/post_images/2019/900_1573573846.png",
        "original": "/uploads/post_images/2019/1573573846.png"
      },
      "thumbnail": "/uploads/post_images/2019/300_1573573846.png"
    },
    "lang": "fa",
    "visit": 0,
    "categories": [
      {
        "id": 2,
        "title": "bbbbbbbb",
        "lang": "fa",
        "parent": 0,
        "pivot": {
          "contents_id": 2,
          "content_categories_id": 2
        }
      }
    ]
  }
]

问题出在这行代码上：

json.decode(response.body)

试试这个：

list = List<KeywordsResponse>.from(response.body.map((x) => KeywordsResponse.fromJson(x)));

list=list.from（response.body.map（（x）=>KeywordsResponse.fromJson（x））；
json.decode
不需要，因为
response.body
已经解码了的
列表
maps@pskink我想将
response.body
返回为
List
formatso调用
response.body
上的
map（）
方法（已对映射的
List
进行json解码）@pskink
response.body.map（（item）=>list.add（关键字response（item['id']，item['title']，item['description']））不起作用
response.body.map（（item）=>KeywordsResponse.fromJson（item））.toList（）
甚至更好：
response.body.map（关键字response.fromJson）.toList（）但我不能100%确定它是否有效
json.decode(response.body)

list = List<KeywordsResponse>.from(response.body.map((x) => KeywordsResponse.fromJson(x)));