Forms 如何在scala playframework中捕获执行异常？

我得到执行异常

[APIRERROR:您必须提供电子邮件地址才能创建票证。]

可以捕获此错误并仅发布

“您必须提供电子邮件地址才能创建票证。”

此错误应显示在查看页面中

给出错误的代码：

val question = uservoice.post("/api/v1/tickets.json", ticket).getJSONObject("ticket")

控制器：

def contactSave = withOptionUser { user => implicit request =>
    contactForm.bindFromRequest.fold(
      formWithErrors => BadRequest(html.anon.contact(user, formWithErrors)),
      c => {
          val uservoice = new com.uservoice.Client(SUBDOMAIN, API_KEY, API_SECRET)

          val ticketMsg = Map("state" -> "open","subject" -> c._2, "message" -> c._3).toMap[String,Object].asJava

          val ticket = Map("email" -> c._1, "ticket" -> ticketMsg).toMap[String,Object].asJava

          Logger.debug(ticket.toString)

          val question = uservoice.post("/api/v1/tickets.json", ticket).getJSONObject("ticket")

          Logger.debug(question.toString)

          Ok(views.html.anon.contactThanks(user))
      }
    )
  }

Html:

@main("Contact Us",user,"contact",stylesheet, scripts) {
    @helper.form(routes.UservoiceController.contactSave) {
<section class="contact">
    <div class="contactBox contentBox">
        <div class="leftColumn">
            <h1>Contact Us</h1>
            <span>You can fill out this form for any general inquiries, comments, etc.</span>
            <span>You can also find us on Facebook and Twitter!</span>

            <div class="social">
                @form.globalError.map { error =>
                <span class="error" data-xpl="loginError">
                    @error.message
                </span>

@main（“联系我们”，用户，“联系”，样式表，脚本）{
@helper.form（routes.UservoiceController.contactSave）{
联系我们
您可以填写此表格以了解任何一般性询问、意见等。
你也可以在Facebook和Twitter上找到我们！
@form.globalError.map{error=>
@错误消息

您可以使用try/catch块创建表单

var form = contactForm.bindFromRequest()
form.fold(
  formWithErrors => ...
  c => {
    ...
    try {
      val question = uservoice.post("/api/v1/tickets.json", ticket).getJSONObject("ticket")
      Logger.debug(question.toString)
      Ok(views.html.anon.contactThanks(user))
    } catch {
      case e: Exception =>
        Logger.error("error ...", e)
        val formWithError = form.withError("email", "You must provide an email address in order to create a ticket.")
        BadRequest(html.anon.contact(user, formWithError))
    }
  }
)

---

在发布到该API之前，您不应该检查有效的电子邮件地址吗？盲目捕获所有异常可能会掩盖其他错误。Hi Limb，代码使用第三方电子邮件发送，我无法找到他们如何验证电子邮件。因此，我想在尝试找出所使用的验证时捕获错误。Hi@Yann Simon I'm getting value withError不是（String，String，String）的成员，正如我在视图文件@（user:Option[user]，form:form[（String，String，String）]）中看到的那样（是的，抱歉，您必须首先提取表单实例：val form=contactForm=contactForm.bindFromRequest form.fold（formWithErrors=>，c=>…请重试{…}catch{…val formWithError=form.withError（…）…}）