Go 戈罗廷没有';不要尊重'ctx.done()`或正确退出
当用户按下Go 戈罗廷没有';不要尊重'ctx.done()`或正确退出,go,Go,当用户按下Ctrl-C时,我试图优雅地退出。我正在尝试输入代码。 包干管 import ( "context" "fmt" "os" "os/signal" "time" ) func main() { ctx := context.Background() // trap Ctrl+C and call cancel on the context ctx, cancel := context.WithCancel(ctx)
Ctrl-C
时,我试图优雅地退出。我正在尝试输入代码。
包干管
import (
"context"
"fmt"
"os"
"os/signal"
"time"
)
func main() {
ctx := context.Background()
// trap Ctrl+C and call cancel on the context
ctx, cancel := context.WithCancel(ctx)
c := make(chan os.Signal, 1)
signal.Notify(c, os.Interrupt)
defer func() {
signal.Stop(c)
cancel()
fmt.Println("Cleaned up")
}()
go func() {
select {
case <-c:
fmt.Println("Got interrupt signal")
cancel()
case <-ctx.Done():
}
fmt.Println("Stopped monitoring")
}()
select {
case <-ctx.Done():
fmt.Println("notified to quit")
case <-time.NewTimer(time.Second * 2).C:
fmt.Println("done something")
}
}
但是,如果正常退出,则无法按预期工作,如下所示:
done something
Cleaned up
我的意思是它应该打印出停止监视的,但不是。在延迟清理
函数中,它调用了cancel()
,这将触发监控goroutine中的选择退出,但不会
如何解决这个问题 谢谢@Zan Lynx,我想出了下面的解决方案
package main
import (
"context"
"fmt"
"os"
"os/signal"
"time"
)
func main() {
ctx := context.Background()
ctx, cancel := context.WithCancel(ctx)
terminated := monitor(ctx, cancel)
defer func() {
cancel()
fmt.Println("Cleaned up")
<-terminated // wait for the monior goroutine quit
}()
select {
case <-ctx.Done():
fmt.Println("notified to quit")
case <-time.NewTimer(time.Second * 1).C:
fmt.Println("done something")
}
}
func monitor(ctx context.Context, cancel context.CancelFunc) <-chan interface{} {
c := make(chan os.Signal, 1)
signal.Notify(c, os.Interrupt)
terminated := make(chan interface{})
go func() {
defer close(terminated)
defer fmt.Println("Stopped monitoring1")
defer signal.Stop(c)
select {
case <-c:
fmt.Println("Got interrupt singnal")
cancel()
case <-ctx.Done():
}
}()
return terminated
}
主程序包
进口(
“上下文”
“fmt”
“操作系统”
“操作系统/信号”
“时间”
)
func main(){
ctx:=context.Background()
ctx,cancel:=上下文。带取消(ctx)
终止:=监视器(ctx,取消)
延迟函数(){
取消
fmt.Println(“已清理”)
您不必等待取消。您只需退出main,点击defer,然后在goroutine运行之前蒸发程序。非常正确,它没有等待goroutine退出。我修改了代码并将其作为答案发布。
package main
import (
"context"
"fmt"
"os"
"os/signal"
"time"
)
func main() {
ctx := context.Background()
ctx, cancel := context.WithCancel(ctx)
terminated := monitor(ctx, cancel)
defer func() {
cancel()
fmt.Println("Cleaned up")
<-terminated // wait for the monior goroutine quit
}()
select {
case <-ctx.Done():
fmt.Println("notified to quit")
case <-time.NewTimer(time.Second * 1).C:
fmt.Println("done something")
}
}
func monitor(ctx context.Context, cancel context.CancelFunc) <-chan interface{} {
c := make(chan os.Signal, 1)
signal.Notify(c, os.Interrupt)
terminated := make(chan interface{})
go func() {
defer close(terminated)
defer fmt.Println("Stopped monitoring1")
defer signal.Stop(c)
select {
case <-c:
fmt.Println("Got interrupt singnal")
cancel()
case <-ctx.Done():
}
}()
return terminated
}