Google bigquery 查询以查找在bigquery中逐个创建的记录

我在玩弄bigquery。给出了以下输入：

+---------------+---------+---------+--------+----------------------+
|   customer    |  agent  |  value  |  city  |   timestamp          |
+---------------+---------+---------+--------+----------------------+
| 1             | 1       |  106    | LA     |  2019-02-12 03:05pm  |
| 1             | 1       |  251    | LA     |  2019-02-12 03:06pm  |
| 3             | 2       |  309    | NY     |  2019-02-12 06:41pm  |
| 1             | 1       |  654    | LA     |  2019-02-12 05:12pm  |
+---------------+---------+---------+--------+----------------------+

我想找到一个又一个代理在5分钟内发出的交易。因此，上表的输出应如下所示：

+---------------+---------+---------+--------+----------------------+
|   customer    |  agent  |  value  |  city  |   timestamp          |
+---------------+---------+---------+--------+----------------------+
| 1             | 1       |  106    | LA     |  2019-02-12 03:05pm  |
| 1             | 1       |  251    | LA     |  2019-02-12 03:06pm  |
+---------------+---------+---------+--------+----------------------+

查询应该以某种方式按代理分组并查找此类事务。但是，从输出中可以看出，结果并没有真正分组。我的第一个想法是使用LEAD函数，但我不确定。你有什么想法吗

查询的想法：

按代理和时间戳描述排序 从第一行开始，用铅看下一行？ 检查时间戳差异是否小于5分钟 如果是，这两行应该在输出中 继续下一个第二排

---

当第二行和第三行也符合条件时，第二行将进入输出，这将导致重复行。我还不知道如何避免这种情况。

一定有更简单的方法，但这能实现你的目标吗

CTE2 AS (
SELECT customer, agent, value, city, timestamp,
  lead(timestamp,1) OVER (PARTITION BY agent ORDER BY timestamp) timestamp_lead,
  lead(customer,1) OVER (PARTITION BY agent ORDER BY timestamp) customer_lead,
  lead(value,1) OVER (PARTITION BY agent ORDER BY timestamp) value_lead,
  lead(city,1) OVER (PARTITION BY agent ORDER BY timestamp) city_lead,
  lag(timestamp,1) OVER (PARTITION BY agent ORDER BY timestamp) timestamp_lag
FROM CTE
)

SELECT agent, 
  if(timestamp_diff(timestamp_lead,timestamp,MINUTE)<5, concat(cast(customer as string),', ',cast(customer_lead as string)),cast(customer as string)) customer, 
  if(timestamp_diff(timestamp_lead,timestamp,MINUTE)<5, concat(cast(value as string),', ',cast(value_lead as string)),cast(value as string)) value,
  if(timestamp_diff(timestamp_lead,timestamp,MINUTE)<5, concat(cast(city as string),', ',cast(city_lead as string)),cast(city as string)) cities,
  if(timestamp_diff(timestamp_lead,timestamp,MINUTE)<5, concat(cast(timestamp as string),', ',cast(timestamp_lead as string)),cast(timestamp as string)) timestamps
FROM CTE2
WHERE (timestamp_diff(timestamp_lead,timestamp,MINUTE)<5 OR NOT timestamp_diff(timestamp,timestamp_lag,MINUTE)<5)

---

下面是BigQuery标准SQL

#standardSQL
SELECT * FROM (
  SELECT *, 
    IF(TIMESTAMP_DIFF(LEAD(ts) OVER(PARTITION BY agent ORDER BY ts), ts, MINUTE) < 5, 
      LEAD(STRUCT(customer AS next_customer, value AS next_value)) OVER(PARTITION BY agent ORDER BY ts), 
    NULL).* 
  FROM `project.dataset.yourtable`
)
WHERE NOT next_customer IS NULL

---

我可能误解了数据，但你能不能不简单地按代理和时间戳排序？是的，这可能是第一步。排序后，必须查看第一行，查看第二行，看看时间戳差异是否小于5分钟，客户是否相同。这应该在所有行中重复。这看起来非常好！非常感谢。这种连接确实有意义。不过，为客户和客户线索设立专栏会更好。当然。当timestamp\u difftimestamp\u lead，timestamp，MINUTE时，只保留现有列和_lead列

#standardSQL
WITH `project.dataset.table` AS (
  SELECT 1 customer, 1 agent, 106 value,'LA' city, '2019-02-12 03:05pm' ts UNION ALL
  SELECT 1, 1, 251,'LA', '2019-02-12 03:06pm' UNION ALL
  SELECT 3, 2, 309,'NY', '2019-02-12 06:41pm' UNION ALL
  SELECT 1, 1, 654,'LA', '2019-02-12 05:12pm' 
), temp AS (
  SELECT customer, agent, value, city, PARSE_TIMESTAMP('%Y-%m-%d %I:%M%p', ts) ts 
  FROM `project.dataset.table`
)
SELECT * FROM (
  SELECT *, 
    IF(TIMESTAMP_DIFF(LEAD(ts) OVER(PARTITION BY agent ORDER BY ts), ts, MINUTE) < 5, 
      LEAD(STRUCT(customer AS next_customer, value AS next_value)) OVER(PARTITION BY agent ORDER BY ts), 
    NULL).* 
  FROM temp
)
WHERE NOT next_customer IS NULL
-- ORDER BY ts

Row customer    agent   value   city    ts                      next_customer   next_value   
1   1           1       106     LA      2019-02-12 15:05:00 UTC 1               251