Google maps -canOpenURL:对于URL:“失败”；谷歌地图：“谷歌地图”错误："；操作无法’；不可能完成

我知道这个问题以前被问过并回答过，但我仍然在调试器控制台中遇到这个错误

2018-07-10 12:55:15.173843+0300布雷克林纳[34011:2595874] -canOpenURL:URL:“comgooglemaps://”失败-错误：“操作无法完成。（OSStatus错误-10814）。”

环境：Xcode 9.4，Swift 3。
请告知如何修复我的实现。希望其他人也会发现它很有用

Info.plist文件

 <key>NSLocationWhenInUseUsageDescription</key>
<string>Will you allow myApp to know your location?</string>
<key>LSApplicationQueriesSchemes</key>
<array>
    <string>tel</string>
    <string>googlechromes</string>
    <string>comgooglemaps</string>
</array>

---

你是否在plist中添加了

comgooglemaps-x-callback

？？将其添加到

LSApplicationQueriesSchemes

下

<key>LSApplicationQueriesSchemes</key>
    <array>
        <string>comgooglemapsurl</string>
        <string>comgooglemaps</string>
        <string>comgooglemaps-x-callback</string>
    </array>

LSApplicationQueriesSchemes
谷歌地图
谷歌地图
comgooglemaps-x-callback

是，您需要如上所述添加到LSApplicationQueriesString。那么您只需要以下几行：

var address = "..."
address = address.replacingOccurrences(of: " ", with: "+")
UIApplication.shared.open(URL(string:"comgooglemaps://?q=\(address)&views=traffic")!, options: [:]) { success in
   if !success {
       UIApplication.shared.open(URL(string: "http://maps.apple.com/?address=\(address)")!)
   }
}

---

你们解决了吗？我解决了，看到答案了吗below@NavNav我的回答解决了你的问题吗？

<key>LSApplicationQueriesSchemes</key>
    <array>
        <string>comgooglemapsurl</string>
        <string>comgooglemaps</string>
        <string>comgooglemaps-x-callback</string>
    </array>

var address = "..."
address = address.replacingOccurrences(of: " ", with: "+")
UIApplication.shared.open(URL(string:"comgooglemaps://?q=\(address)&views=traffic")!, options: [:]) { success in
   if !success {
       UIApplication.shared.open(URL(string: "http://maps.apple.com/?address=\(address)")!)
   }
}