Graphql （中继）根据查询结果重新运行查询的正确语法是什么

假设我有一个查询，它得到一个

advisors

。该查询返回连接到该advisor的advisor

id

s的列表。现在我想重新运行首先得到advisor的查询，使用

n

ids的

number，并得到那些advisor。我只需要做一次，而不是递归

const query = graphql`
  query AdvisorProfileQuery($id: ID!) {
    advisor: node(id: $id) {
      ... on Advisor {
        name
        assignments (first: 100) {
          edges {
            node {
              id <---- i want these ids and plug them back into the query to just get "name" of the list of ids
            }
          }
        }
      }
    }
  }
`;

const QueryRenderer = LoadingQueryRenderer(AdvisorProfile, query);
export default ({ i18n }) => {
  const { id } = useParams();
  return (
    <>
      <QueryRenderer params={{ id: id }} />
    </>
  );
};

const query=graphql`
查询AdvisorProfileQuery（$id:id！）{
顾问：节点（id:$id）{
…关于顾问{
名称
作业（第一次：100）{
边缘{
节点{
身份证{
const{id}=useParams（）；
返回(
);
};
答案是创建一个片段，并将其放在

父组件

const query = graphql`
  query AdvisorProfileQuery($id: ID!) {
    advisor: node(id: $id) {
      ... on Advisor {
        ... BottomCardTable_advisor
        name
      }
    }
  }
`;

const QueryRenderer = LoadingQueryRenderer(AdvisorProfile, query);
export default ({ i18n }) => {
  const { id } = useParams();
  return (
    <>
      <QueryRenderer params={{ id: id }} />
    </>
  );
};

export default createFragmentContainer(TableComponent, graphql`
  fragment BottomCardTable_advisor on Advisor {
    assignments: assignments (first: 100) {
      edges {
        node {
          id
          primaryName
          primaryEmail
          assignedOn
          type
        }
      }
    }
  }
`);