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Groovy 未来get从executor服务提交返回null_Groovy - Fatal编程技术网

Groovy 未来get从executor服务提交返回null

Groovy 未来get从executor服务提交返回null,groovy,Groovy,在执行Java到Groovy代码迁移的初始阶段时,我遇到了一个问题,Groovy版本从未来返回null,而Java返回正确的整数(123) J1.java和G1.groovy之间的唯一更改是类名和lambda到闭包的转换 //文件:J1.java import java.util.concurrent.ExecutorService; import java.util.concurrent.Executors; import java.util.concurrent.Future; public

在执行Java到Groovy代码迁移的初始阶段时,我遇到了一个问题,Groovy版本从未来返回null,而Java返回正确的整数(123)

J1.java和G1.groovy之间的唯一更改是类名和lambda到闭包的转换

//文件:J1.java

import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
import java.util.concurrent.Future;
public class J1 {
  public static void main (String... args) throws Exception {
    ExecutorService executor = Executors.newFixedThreadPool (1);
    Future<Integer> future = executor.submit (() -> 123);
    System.out.println ("Result: " + future.get ());
    executor.shutdown ();
  }
}

在Groovy中,闭包是
可运行的
可调用的

不幸的是,当您调用
executor.submit{..}
时,运行库选择调用
executor.submit(Runnable)
,而该调用不返回值

您应该显式地将闭包强制转换为可调用的:

def executor = Executors.newFixedThreadPool(1)
def future = executor.submit ({ -> 123 } as Callable)
println "Result: ${future.get()}"
executor.shutdown()
Groovy: 2.4.5
Java: 1.8 64-bit
Platform: Windows 7 64-bit
def executor = Executors.newFixedThreadPool(1)
def future = executor.submit ({ -> 123 } as Callable)
println "Result: ${future.get()}"
executor.shutdown()