Hibernate @EntityListener从未被wildlfy 10解雇

我有这样一个实体：

@Entity
@EntityListeners (Rserve.class)
public class Example extends Analysis {
  private @Column @Basic int a;
  private @Column @Basic int b = 1;
  private @Column @Basic int c;
  //...
}

public class Rserve extends Agent <R> { /* R is an annotation ... */ }

public abstract class Agent <E extends Annotation> {
  {
    System.out.println ("CREATING " + getClass ().getSimpleName ());
  }

  @PrePersist
  @PreUpdate
  @PreRemove
  @PostPersist
  @PostRemove
  @PostLoad
  @PostUpdate
  public void cb (Object a) {
    System.out.println ("CB(" + a + ")");
  }
}

<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.0"
  xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
  xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
  <persistence-unit name="mev" transaction-type="JTA">
    <provider>org.hibernate.jpa.HibernatePersistenceProvider</provider>

    <properties>
      <property name="hibernate.connection.url" value="jdbc:h2:mem:mev;DB_CLOSE_DELAY=-1" />
      <property name="hibernate.dialect" value="org.hibernate.dialect.H2Dialect"></property>
      <property name="hibernate.connection.driver_class" value="org.h2.Driver" />
      <property name="hibernate.hbm2ddl.auto" value="update" />
      <property name="hibernate.connection.release_mode" value="after_transaction" />
      <property name="hibernate.connection.password" value="admin" />
      <property name="hibernate.connection.username" value="admin" />
    </properties>
  </persistence-unit>
</persistence>

听众喜欢这样：

@Entity
@EntityListeners (Rserve.class)
public class Example extends Analysis {
  private @Column @Basic int a;
  private @Column @Basic int b = 1;
  private @Column @Basic int c;
  //...
}

public class Rserve extends Agent <R> { /* R is an annotation ... */ }

public abstract class Agent <E extends Annotation> {
  {
    System.out.println ("CREATING " + getClass ().getSimpleName ());
  }

  @PrePersist
  @PreUpdate
  @PreRemove
  @PostPersist
  @PostRemove
  @PostLoad
  @PostUpdate
  public void cb (Object a) {
    System.out.println ("CB(" + a + ")");
  }
}

<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.0"
  xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
  xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
  <persistence-unit name="mev" transaction-type="JTA">
    <provider>org.hibernate.jpa.HibernatePersistenceProvider</provider>

    <properties>
      <property name="hibernate.connection.url" value="jdbc:h2:mem:mev;DB_CLOSE_DELAY=-1" />
      <property name="hibernate.dialect" value="org.hibernate.dialect.H2Dialect"></property>
      <property name="hibernate.connection.driver_class" value="org.h2.Driver" />
      <property name="hibernate.hbm2ddl.auto" value="update" />
      <property name="hibernate.connection.release_mode" value="after_transaction" />
      <property name="hibernate.connection.password" value="admin" />
      <property name="hibernate.connection.username" value="admin" />
    </properties>
  </persistence-unit>
</persistence>

---

这似乎是一个Wildfly问题，它没有回调实体侦听器的超类。回调在放入监听器的具体类时工作良好，根据Klaus Groenbaek的说法，在Spring Boot中甚至在超类上也工作良好。

这似乎是一个Wildfly问题，没有回调实体监听器的超类。回调在放入监听器的具体类时可以很好地工作，根据Klaus Groenbaek的说法，在Spring Boot中甚至在超类上也可以很好地工作。

我不确定与监听器相关的注释是否可以在抽象类中，它应该根据我发现的其他资源和其他资源。不过，显然你是对的，bummer！我不确定那些与监听器相关的注释是否可以是一个抽象的类，它应该是根据我发现的其他资源，显然你是对的，笨蛋！