Hive 蜂巢相当于LISTAGG

我在oracle中有一个这样的查询，但我需要一个与此对应的配置单元SQL。有人能告诉我下面的配置单元对应的是什么吗

组内的“[”| | listag（t3.measure_title“；”）（按t3.measure_title排序）| |]]所有的|度量值|说明。如何在配置单元中重写这些内容

我在Oracle中的查询是

SELECT 
    t1.member_id,
    t2.first_name,
    t2.date_of_birth_sk,
    '[' || LISTAGG(t3.measure_title, ';') WITHIN GROUP (ORDER BY t3.measure_title) || ']' all_measure_desc
FROM qms_gic_lifecycle t1 
INNER JOIN dim_member t2 
on t1.member_id = t2.member_id
INNER JOIN dim_quality_measure t3 
on t1.quality_measure_id = t3.quality_measure_id
GROUP BY  
    t1.member_id,
    t2.first_name,
    t2.date_of_birth_sk;

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根据重复值的处理方式，您可以使用

collect\u list

或

collect\u set

<代码>收集列表保留重复值，而

收集集

消除重复值

输出将是一个值数组

SELECT 
    t1.member_id,
    t2.first_name,
    t2.date_of_birth_sk,
    COLLECT_LIST(t3.measure_title) as all_measure_desc
FROM qms_gic_lifecycle t1 
INNER JOIN dim_member t2 
on t1.member_id = t2.member_id
INNER JOIN dim_quality_measure t3 
on t1.quality_measure_id = t3.quality_measure_id
GROUP BY  
    t1.member_id,
    t2.first_name,
    t2.date_of_birth_sk;

根据重复值的处理方式，可以使用collect_list或collect_set。collect_list保留重复值，而collect_set消除重复值

输出将是一个值数组

SELECT 
    t1.member_id,
    t2.first_name,
    t2.date_of_birth_sk,
    COLLECT_LIST(t3.measure_title) as all_measure_desc
FROM qms_gic_lifecycle t1 
INNER JOIN dim_member t2 
on t1.member_id = t2.member_id
INNER JOIN dim_quality_measure t3 
on t1.quality_measure_id = t3.quality_measure_id
GROUP BY  
    t1.member_id,
    t2.first_name,
    t2.date_of_birth_sk;

您可以使用concat_ws（string SEP，array）函数将结果数组转换为字符串

concat_ws(',', COLLECT_LIST(t3.measure_title) ) as all_measure_desc

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请提供更多关于您答案的详细信息，以帮助其他人理解。