Hive 如何替换配置单元列中的特殊字符?

Hive 如何替换配置单元列中的特殊字符?,hive,regexp-replace,Hive,Regexp Replace,我在hive中有一个需求,需要将非字母数字字符替换为u。 栏中数据为“Pranav_Wagde_job_1163_W.Pranav Ltr简历04.07.2016.pdf” 输出是 Pranav_Wagde_job_1163_W.Pranav Ltr-Resume 04.07.2016.pdf 我无法替换文件名中的点。 如何替换数据中除文件扩展名以外的所有点?如果支持正向前瞻,则可以添加一个替代项|来匹配所有点,但右侧有1+个字字符后跟字符串末尾的点除外 (?:[^0-9a-zA-Z._]|\

我在hive中有一个需求,需要将非字母数字字符替换为u。 栏中数据为“Pranav_Wagde_job_1163_W.Pranav Ltr简历04.07.2016.pdf”

输出是

Pranav_Wagde_job_1163_W.Pranav Ltr-Resume 04.07.2016.pdf
我无法替换文件名中的点。
如何替换数据中除文件扩展名以外的所有点?

如果支持正向前瞻,则可以添加一个替代项
|
来匹配所有点,但右侧有1+个字字符后跟字符串末尾的点除外

(?:[^0-9a-zA-Z._]|\.(?!\w+$))

如果支持正向前瞻,则可以添加一个替代项
|
来匹配所有点,但右侧有1+个单词字符后跟字符串末尾的点除外

(?:[^0-9a-zA-Z._]|\.(?!\w+$))

2009/pp>p>p>p>p>p>p>p>p>p>p>p>p>p>p>p>p>p>p>p>p>p>p>p>p>p>p>p>p>p>p>p>p>p>p>p>p>p>p>p>获得获得输出的结果,得到得到得到得到的输出的输出作为作为作为作为作为作为作为,UUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUU鸟。您的RegExp正在使用您在超链接中提供的工具,但不幸的是,它在配置单元中不起作用。我得到的输出是“Pranav\u Wagde\u job\u 1163\u W\u Pranav\u Ltr\u Resume\u 04\u 07\u 2016\u pdf”`尝试将另一个反斜杠重复两次,就像
\\W+/code>@Pranav整个模式将是
(?:[^0-9a-zA-Z.\u124\\(?!\\ W+$)该公司的代码<获取该公司的代码代码>获取该公司的代码>获取该公司的代码>获取该公司的输出为获得该公司的输出为:UUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUU鸟。您的RegExp正在使用您在超链接中提供的工具,但不幸的是,它在配置单元中不起作用。我得到的输出是“Pranav\u Wagde\u job\u 1163\u W\u Pranav\u Ltr\u Resume\u 04\u 07\u 2016\u pdf”`试着将另一个反斜杠加倍,就像
\\W+/code>@Pranav整个模式将是
(?:[0-9a-zA-Z.]124\.(?!\\ W+$)