通过xpath选择器从html标记列表中选择特定的html标记

我想从以下html代码中获得一些特定信息：

<div class="main">    
    <div class="a"><div><a>linkname1</a></div></div> <!-- I DON'T want get the text of this 'a' tag --> 
    <div class="b">xxx</div>
    <div class="c">xxx</div>
    <div class="a"><div><a>linkname2</a></div></div> <!-- I want get the text of this 'a' tag --> 
    <div class="a"><div><a>linkname3</a></div></div> <!-- I want get the text of this 'a' tag --> 
    <div class="a"><div><a>linkname4</a></div></div> <!-- I want get the text of this 'a' tag -->  
    <div class="a"><div><a>linkname5</a></div></div> <!-- I want get the text of this 'a' tag --> 
    <div class="d"></div>
    <div class="c">xxx</div>
    <div class="a"><div><a>linkname6</a></div></div> <!-- I DON'T want get the text of this 'a' tag --> 
    <div class="a"><div><a>linkname7</a></div></div> <!-- I DON'T want get the text of this 'a' tag --> 
    <div class="a"><div><a>linkname8</a></div></div> <!-- I DON'T want get the text of this 'a' tag --> 
    <div class="d"></div>
    <div class="c">xxx</div>
    <div class="a"><div><a>linkname9</a></div></div> <!-- I DON'T want get the text of this 'a' tag --> 
    <div class="a"><div><a>linkname10</a></div></div> <!-- I DON'T want get the text of this 'a' tag --> 
</div>

---

谢谢：）

您可以尝试以下表达式：

/div/div[position() > 3 and position() < 8]/div/a/text()

/div/div[position（）>3和position（）<8]/div/a/text（）

我找到了一个可能的解决方案：）

您的问题是一个集合问题，如本SO答案中所述：

因此，根据您的具体情况，您应该使用如下交叉口：

(: intersection :)
$set1[count(. | $set2) = count($set2)]

div[@class='c'][1]/following-sibling::*[count(. | current()/div[@class='d'][1]/preceding-sibling::*) = count(current()/div[@class='d'][1]/preceding-sibling::*)]

set1应该是

div[@class='c']

和
set2应该是

div[@class='d']

前面的集合

现在，根据上面的公式将两者结合起来

set1 = "div[@class='c'][1]/following-sibling::*" and
set2 = "div[@class='d'][1]/preceding-sibling::*"

XPath表达式可能如下所示：

(: intersection :)
$set1[count(. | $set2) = count($set2)]

div[@class='c'][1]/following-sibling::*[count(. | current()/div[@class='d'][1]/preceding-sibling::*) = count(current()/div[@class='d'][1]/preceding-sibling::*)]

输出：

linkname2
linkname3
linkname4
linkname5

---

你试了什么？显示您当前的XPathI尝试了几件事。我最后一次尝试是：//div[@class=“main”]/following:：div[count（previous:：div[@class=“c”]）=1]/div/a/text（），但我什么也没有得到：/对不起，我没有说类“a”的div数可能不同，我不能使用像3或8这样的“硬编码”值