Html Fileupload控件始终返回Hasfile属性false

我正在尝试上载文件，但上载控件返回的总是false，因为我下面的代码无法使用该文件。我正在提交将文件存储在数据库中的按钮事件。谁能告诉我哪里出了问题

谢谢

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文件上载控件与UpdatePanel不兼容。你有两个选择

将控件移到UpdatePanel之外

如果不可能，请在UpdatePanel上添加PostBackTrigger 一个例子 FileUpload控件与UpdatePanel不兼容。你有两个选择

将控件移到UpdatePanel之外 如果不可能，请在UpdatePanel上添加PostBackTrigger 一个例子

<Triggers>
   <asp:PostBackTrigger ControlID="yourButtonIdThatSubmitsFile" />
</Triggers>

---

文件上载控件与UpdatePanel不兼容。你有两个选择

将控件移到UpdatePanel之外

如果不可能，请在UpdatePanel上添加PostBackTrigger 一个例子 FileUpload控件与UpdatePanel不兼容。你有两个选择

将控件移到UpdatePanel之外 如果不可能，请在UpdatePanel上添加PostBackTrigger 一个例子

<Triggers>
   <asp:PostBackTrigger ControlID="yourButtonIdThatSubmitsFile" />
</Triggers>

---

您也可以使用jquery上传文件

JS函数

function SaveFiles() {

    var fileInput = document.getElementById('fileInput');
    var file = $("#fileInput").val();

    if (file.length > 0) {
        var fd = new FormData();
        var xhr = new XMLHttpRequest();
        xhr.open('POST', '/Admin/UploadImage');
        xhr.setRequestHeader('Content-type', 'multipart/form-data');

        //Appending file information in Http headers
        xhr.setRequestHeader('X-File-Name', fileInput.files[0].name);
        xhr.setRequestHeader('X-File-Type', fileInput.files[0].type);
        xhr.setRequestHeader('X-File-Size', fileInput.files[0].size);
        xhr.setRequestHeader['X-File-FileName', 1];
        xhr.setRequestHeader['X-File-Id', id];

        //Sending file in XMLHttpRequest
        xhr.send(fileInput.files[0]);
        xhr.onreadystatechange = function (data) {

            if (xhr.readyState == 4 && xhr.status == 200) {

                alert("Image Uploaded Successfully...");

            }
        }
    }
}

**C# Code**

public JsonResult UploadImage()
        {
            string fileName = Request.Headers["X-File-Name"];
            string fileType = Request.Headers["X-File-Type"];
            int fileSize = Convert.ToInt32(Request.Headers["X-File-Size"]);

            System.IO.Stream fileContent = Request.InputStream;
            System.IO.FileStream fileStream = System.IO.File.Create(Server.MapPath("~/UploadImg/" + fileName));
            fileContent.Seek(0, System.IO.SeekOrigin.Begin);

            //Copying file's content to FileStream
            fileContent.CopyTo(fileStream);
            fileStream.Dispose();

            string FileName = Server.MapPath("~/UploadImg/" + fileName);

            //Here you can code for insert in database

            return Json(FileName);
        }

---

您也可以使用jquery上传文件

JS函数

function SaveFiles() {

    var fileInput = document.getElementById('fileInput');
    var file = $("#fileInput").val();

    if (file.length > 0) {
        var fd = new FormData();
        var xhr = new XMLHttpRequest();
        xhr.open('POST', '/Admin/UploadImage');
        xhr.setRequestHeader('Content-type', 'multipart/form-data');

        //Appending file information in Http headers
        xhr.setRequestHeader('X-File-Name', fileInput.files[0].name);
        xhr.setRequestHeader('X-File-Type', fileInput.files[0].type);
        xhr.setRequestHeader('X-File-Size', fileInput.files[0].size);
        xhr.setRequestHeader['X-File-FileName', 1];
        xhr.setRequestHeader['X-File-Id', id];

        //Sending file in XMLHttpRequest
        xhr.send(fileInput.files[0]);
        xhr.onreadystatechange = function (data) {

            if (xhr.readyState == 4 && xhr.status == 200) {

                alert("Image Uploaded Successfully...");

            }
        }
    }
}

**C# Code**

public JsonResult UploadImage()
        {
            string fileName = Request.Headers["X-File-Name"];
            string fileType = Request.Headers["X-File-Type"];
            int fileSize = Convert.ToInt32(Request.Headers["X-File-Size"]);

            System.IO.Stream fileContent = Request.InputStream;
            System.IO.FileStream fileStream = System.IO.File.Create(Server.MapPath("~/UploadImg/" + fileName));
            fileContent.Seek(0, System.IO.SeekOrigin.Begin);

            //Copying file's content to FileStream
            fileContent.CopyTo(fileStream);
            fileStream.Dispose();

            string FileName = Server.MapPath("~/UploadImg/" + fileName);

            //Here you can code for insert in database

            return Json(FileName);
        }

---

将

page_load

方法添加到受保护的void page_load（对象发送方，事件参数e）{if（！IsPostBack）{MultiView1.ActiveViewIndex=0；}aluminard_lblStatus.Text=“”；}将您的

page_load

方法添加到受保护的void page_load（对象发送方，事件参数e）{if（！IsPostBack）{MultiView1.ActiveViewIndex=0；}alumnium_lblStatus.Text=“”；}我正在使用multiview查看我正在保存的所有详细信息，包括图片上传按钮点击我正在使用multiview我正在保存的所有详细信息，包括图片上传按钮点击