Html 如何解析下一页的美丽汤？

我使用下面的代码解析下一页的页面：

def parseNextThemeUrl(url):
  ret = []
  ret1 = []
  html = urllib.request.urlopen(url)
  html = BeautifulSoup(html, PARSER)
  html = html.find('a', class_='pager_next')
  if html:
    html = urljoin(url, html.get('href'))
    ret1 = parseNextThemeUrl(html)

    for r in ret1:
        ret.append(r)
  else:
    ret.append(url)
  return ret

但我得到的错误如下，我如何才能解析下一个链接，如果有一个链接

Traceback (most recent call last):
html = urllib.request.urlopen(url)
File "/Library/Frameworks/Python.framework/Versions/3.5/lib/python3.5/urllib/request.py", line 162, in urlopen
return opener.open(url, data, timeout)
File "/Library/Frameworks/Python.framework/Versions/3.5/lib/python3.5/urllib/request.py", line 456, in open
req.timeout = timeout
AttributeError: 'list' object has no attribute 'timeout'

---

我的答案如下：

def parseNextThemeUrl(url):
  urls = []
  urls.append(url)
  html = urllib.request.urlopen(url)
  soup = BeautifulSoup(html, 'lxml')
  new_page = soup.find('a', class_='pager_next')

  if new_page:
    new_url = urljoin(url, new_page.get('href'))
    urls1 = parseNextThemeUrl(new_url)

    for url1 in urls1:
        urls.append(url1)
  return urls

---

你能给我们网络链接吗？如果不了解网页，我们无法确定多少内容。

http://003.b2btoys.net/en/ProductList.aspx?Class1=12

http://003.b2btoys.net/en/ProductList.aspx?PageIndex=2&Class1=13&Class2=0&type=&keyWord=