Ios 类型'；ChatViewController'；没有成员'；showOrHideKeyboard&x27；

我似乎找不到我所做的功能

错误：类型“ChatViewController”没有成员“showOrHideKeyboard”

代码：

---

您应该用

objc

换行

func showOrHideKeyboard(notification: NSNotification) {
}

这条线

@objc func showOrHideKeyboard(_ notification: NSNotification) {
}

使用以下任一选项：

@objc func showOrHideKeyboard(_ notification: NSNotification) 
#selector(ChatViewController.showOrHideKeyboard(_:))

或：

请注意函数签名中的

和

#selector

swift最新版本似乎不再支持带有函数名但没有参数名的#selector”（35;：）”

只需替换并填充参数名称或使用自动完成键入声明：

#selector(ViewController.showOrHideKeyboard(notification:)

---

优化您的代码，如下所示

在ViewDidLoad（）中

创建一个函数

// MARK: - Notification Observered
    /// Notification received
    @objc func notificationObservered(notification: NSNotification) {

        switch notification.name {
        case NSNotification.Name.UIKeyboardWillShow:
            break
        case NSNotification.Name.UIKeyboardWillHide:
            // let info = notification.userInfo!
            // let keyboardFrame: CGRect = (info[UIKeyboardFrameEndUserInfoKey] as! NSValue).cgRectValue
           break
        default:
            break
        }
    }

---

@JohnDoe您是否为showOrHideKeyboard方法添加了objc？@JohnDoe答案已更新，请检查并接受答案。嗯，答案仍然相同？那就不必了work@JohnDoe请检查方法声明。要查看您的信息，请选中编辑历史请记住下划线

\uuu

，如果不将其放入，则它将不起作用

#selector(ViewController.showOrHideKeyboard(notification:)

[NSNotification.Name.UIKeyboardWillShow,
         NSNotification.Name.UIKeyboardWillHide].forEach { (notificationName) in
            NotificationCenter.default.addObserver(self, selector: #selector(notificationObservered(notification:)),
                                                   name: notificationName, object: nil)
        }

// MARK: - Notification Observered
    /// Notification received
    @objc func notificationObservered(notification: NSNotification) {

        switch notification.name {
        case NSNotification.Name.UIKeyboardWillShow:
            break
        case NSNotification.Name.UIKeyboardWillHide:
            // let info = notification.userInfo!
            // let keyboardFrame: CGRect = (info[UIKeyboardFrameEndUserInfoKey] as! NSValue).cgRectValue
           break
        default:
            break
        }
    }