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Ios 如何根据条件设置初始视图控制器?_Ios_Objective C_Iphone_Storyboard - Fatal编程技术网

Ios 如何根据条件设置初始视图控制器?

Ios 如何根据条件设置初始视图控制器?,ios,objective-c,iphone,storyboard,Ios,Objective C,Iphone,Storyboard,根据用户是否登录到服务器的条件显示不同的模板。如果用户未登录到应用程序服务器,则需要显示LoginViewController[UIViewController],否则显示选项卡BarViewController[UITabBarViewController] 因为我是第一次使用故事板。有谁能建议我在情节提要中处理这种情况吗?您可以通过情节提要名称选择ViewController: UIStoryboard *yourStoryboard = [UIStoryboard storyboardW

根据用户是否登录到服务器的条件显示不同的模板。如果用户未登录到应用程序服务器,则需要显示LoginViewController[
UIViewController
],否则显示选项卡BarViewController[
UITabBarViewController
]


因为我是第一次使用故事板。有谁能建议我在情节提要中处理这种情况吗?

您可以通过情节提要名称选择ViewController:

 UIStoryboard *yourStoryboard = [UIStoryboard storyboardWithName:@"yourstoryboard"
                                                          bundle:nil];
 YourViewController *vc = [yourStoryboard instantiateViewControllerWithIdentifier:@"yourViewControllerIdentifier"];

然后显示
vc
在应用程序代理的
应用程序中创建窗口和所需的初始视图控制器:didFinishLaunchingWithOptions:
方法:

self.window = [[UIWindow alloc] initWithFrame:UIScreen.mainScreen.bounds];  
UIStoryboard *storyboard = [UIStoryboard storyboardWithName:@"Main" bundle:nil];
if ([self isUserLoggedIn]) {  
    // Show the dashboard
    self.window.rootViewController = [storyboard instantiateViewControllerWithIdentifier:@"TabBarViewcontroller"];
} else {
    // Login
    self.window.rootViewController = [storyboard instantiateViewControllerWithIdentifier:@"LoginViewController"];
}
[self.window makeKeyAndVisible];
我是这样做的

首先,创建名为LoginViewController的东西。它实现了您的登录逻辑。您的根控制器是uitabarcontroller

现在在AppDelegate中:

- (void) doLogin:(NSDictionary *)dict
{
        TransactionsViewController *transactions;
        BalancesViewController *balances;
        ProfileViewController *profile;
        UINavigationController *navi;
        UITabBarController *root;

        root = (UITabBarController *)self.window.rootViewController;

        navi = [root.viewControllers objectAtIndex:0];
        transactions = [navi.viewControllers objectAtIndex:0];
        transactions.delegate = self;

        navi = [root.viewControllers objectAtIndex:1];
        balances = [navi.viewControllers objectAtIndex:0];
        balances.delegate = self;

        navi = [root.viewControllers objectAtIndex:2];
        profile = [navi.viewControllers objectAtIndex:0];
        profile.delegate = self;

        [transactions loadDataFromLogin:dict];
        [balances loadDataFromLogin:dict];
        [profile loadDataFromLogin:dict];
}

- (void) showLoginView
{
        assert(loginController == nil);
        assert(activityView == nil);

        UITabBarController *tabbar = (UITabBarController *)self.window.rootViewController;
        loginController = [tabbar.storyboard instantiateViewControllerWithIdentifier:@"LoginViewController"];
        loginController.delegate = self;
        [tabbar presentModalViewController:loginController animated:YES];
}

- (void) loginWithLogin:(NSDictionary *)dict relogin:(BOOL)relogin
{
        NSString *_login = [dict valueForKey:@"email"];
        NSString *_pass = [dict valueForKey:@"pass"];
        NetworkOperation *op = [NetworkOperation operationLogin:_login pass:_pass];
        [NetworkOperation enqueueOperation:op observer:self];
        if (!relogin && !loginController)
                [self doLogin:dict];
}

- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions
{
        session = nil;
        loginController = nil;

        return YES;
}

- (void)applicationDidBecomeActive:(UIApplication *)application
{
        // Restart any tasks that were paused (or not yet started) while the application was inactive. If the application was previously in the background, optionally refresh the user interface.
        NSString *login = [[NSUserDefaults standardUserDefaults] stringForKey:@"email"];
        NSString *pass = [[NSUserDefaults standardUserDefaults] stringForKey:@"pass"];
        NSString *name = [[NSUserDefaults standardUserDefaults] stringForKey:@"name"];
        if ((login == nil || login.length == 0) ||
            (pass == nil || pass.length == 0) ||
            (name == nil || name.length == 0)) {
                if (!loginController) {
                        [self.window makeKeyAndVisible];
                        [self performSelector:@selector(showLoginView) withObject:nil afterDelay:0.1];
                }
        } else {
                NSDictionary *dict = [NSDictionary dictionaryWithObjectsAndKeys:login, @"email",
                                      pass, @"pass", name, @"name", nil];
                [self loginWithLogin:dict relogin:(session != nil)];
        }
}
因此,您的应用程序代理会检查您是否存储了通行证和登录名。如果是,则使用它们登录并切换到根视图控制器。在我的例子中,它是选项卡式的,显示带有余额、交易等的两个选项卡

如果没有登录并通过,则在根视图控制器的顶部显示登录视图控制器

这里@session是您当前的会话。登录正在使用您在代码中看到的排队操作


如果您需要更多详细信息,只需ping我即可。

UIStoryboard*storyboard=[UIStoryboard storyboard with name:@“Main”bundle:nil]; 如果([self isUserLoggedIn]){
//显示仪表板 self.window.rootViewController=[storyboard InstanceDeviceController WithiIdentifier:@“first”]; }否则{ //登录 self.window.rootViewController=[storyboard InstanceDeviceController WithiIdentifier:@“second”]; }

可能重复的可能重复的