Ios Json加速器和AFN网络

当操作运行时，我不能在加速器创建的JSON模型中输入数据。 你能告诉我我做错了什么吗

{
    [super viewDidLoad];

NSLog(@"you are in a tableViewController");
self.title = @"NavigationOrdini";


NSURLRequest *req = [NSURLRequest requestWithURL:[NSURL URLWithString:@"http://www.stampa6x3.com/json.php?azione=ordini"]];
AFJSONRequestOperation* operation;

operation = [AFJSONRequestOperation JSONRequestOperationWithRequest:req
                                                            success:^(NSURLRequest *request, NSURLResponse *response, id JSON)
{

    [[ordiniModel alloc] initWithDictionary:JSON];



}
             failure:^(NSURLRequest *request, NSURLResponse *response, NSError
                       *error, id JSON) {
                 [self setTitle:@"Dictionary"];
                 NSLog(@"failed! %d",[error code]);
             }];
[operation start];


ordiniModel*test;

NSLog(@"il valore è %@",test.ordini.description);

}

---

AFJSONRequestOperation是异步的，这意味着当应用程序的其余部分运行时，代码将继续执行。完成块在代码实际完成时运行

因此，请尝试：

NSLog(@"you are in a tableViewController");
self.title = @"NavigationOrdini";
ordiniModel *test;  // <-- create variable here

NSURLRequest *req = [NSURLRequest requestWithURL:[NSURL URLWithString:@"http://www.stampa6x3.com/json.php?azione=ordini"]];
AFJSONRequestOperation* operation;

operation = [AFJSONRequestOperation JSONRequestOperationWithRequest:req
                                                            success:^(NSURLRequest *request, NSURLResponse *response, id JSON)
{

    test = [[ordiniModel alloc] initWithDictionary:JSON]; // <-- Assign here
    NSLog(@"il valore è %@",test.ordini.description);


}
             failure:^(NSURLRequest *request, NSURLResponse *response, NSError
                       *error, id JSON) {
                 [self setTitle:@"Dictionary"];
                 NSLog(@"failed! %d",[error code]);
             }];
[operation start];

NSLog（@“您在tableViewController中”）；
self.title=@“NavigationOrdini”；
OrdinModel*测试；//你能说得更具体些吗？你得到了什么样的回应？您是否收到错误？响应正常！无错误[test initWithDictionary:JSON]//