Ios 使用解析从通讯簿添加好友
我正在构建一个应用程序,在注册/登录时,它将浏览用户通讯簿,获取电话号码,在解析时对照用户类中的电话号码列进行检查,如果他们不是朋友,则添加他们 我在AddressBookHelper.swift中有一个功能来帮助获取电话号码:Ios 使用解析从通讯簿添加好友,ios,swift,parse-platform,addressbook,relation,Ios,Swift,Parse Platform,Addressbook,Relation,我正在构建一个应用程序,在注册/登录时,它将浏览用户通讯簿,获取电话号码,在解析时对照用户类中的电话号码列进行检查,如果他们不是朋友,则添加他们 我在AddressBookHelper.swift中有一个功能来帮助获取电话号码: class AddressBookHelper: NSObject { let addressBook = AFAddressBookManager() static var addressBookData = AFAddressBookManager.allCon
class AddressBookHelper: NSObject {
let addressBook = AFAddressBookManager()
static var addressBookData = AFAddressBookManager.allContactsFromAddressBook()
static var contactsArray = [String]()
static func getContacts() -> [String] {
var array = [String]()
for contact in addressBookData{
let phoneNumberArray = contact.numbers as! [String]
for number in phoneNumberArray{
array.append(number)
}
}
return array
}
}
然后在ParseHelper.swift中,我再次检查Parse User类:
static func lookUpUserFromAddressBook(addressBook: [String], completionBlock: PFArrayResultBlock) {
for numbers in addressBook{
let query = User.query()
query!.whereKey("telephone", equalTo:numbers)
query!.findObjectsInBackgroundWithBlock(completionBlock)
}
}
最后,单击按钮时,我将用户添加为朋友(如果还不是朋友):
@IBAction func importContacts(sender: AnyObject) {
ParseHelper.lookUpUserFromAddressBook(AddressBookHelper.getContacts()) {
(results: [AnyObject]?, error: NSError?) -> Void in
if error == nil {
if let objects = results as? [PFObject] {
for object in objects {
let userObject = object as! User
self.matchedUsers.append(userObject)
let query = PFQuery(className: "Friends")
query.includeKey("toUser")
query.whereKey("fromUser", equalTo: User.currentUser()!)
query.findObjectsInBackgroundWithBlock {
(objects: [AnyObject]?, error: NSError?) -> Void in
if error == nil {
if (objects!.count == 0) {
ParseHelper.addFollowRelationshipFromUser(fromUser: User.currentUser()!, toUser: userObject, completionBlock: { (success, error) -> Void in
if success{
self.performSegueWithIdentifier("skipped", sender: self)
}
else{
print("Error: \(error!) \(error!.userInfo)")
}
})
}
else{
self.performSegueWithIdentifier("skipped", sender: self)
}
} else {
print("Error: \(error) \(error!.userInfo)")
}
}
}
}
}
else {
print("Error: \(error!) \(error!.userInfo)")
}
}
}
我这样做对吗?它可以工作,但代码似乎有点长。有没有更简单的方法
提前感谢您应该看看PFQuery的
whereKey:containedIn:
。这将返回所有用户的列表,这些用户的电话号码与您在数组中传递的任何号码匹配。这将大大减少检索用户联系人所需的查询数量
// Find users with any of these phone numbers
let numbers = ["1234567890", "1111111111", "222222222"]
query.whereKey("phoneNumber", containedIn: numbers)
从《解析iOS开发人员指南》中:
如果要检索与多个不同值匹配的对象,可以
可以使用whereKey:containedIn:,提供可接受的
价值观用单个查询替换多个查询通常很有用
询问
您还可以使用PFObject.saveAllInBackground()在一个查询中创建以下所有关系,它需要保存一个PFObjects数组。是否更改此帮助?静态func lookUpUserFromAddressBook(addressBook:[String],completionBlock:PFArrayResultBlock){let query=User.query()query!。whereKey(“电话”,包含在:addressBook)query!。FindObjectsInBackgroundithBlock(completionBlock)}是的,这是一件有帮助的事情。