Ios5 iphone应用程序中的sqlite3

我在sqlite3表中构建。执行以下选择命令时：

select us.saleSpecificProduct,us.fAtMall,u.name,u.gender,st.storeName
  from UsersSale us,Users u,Stores st
 where u.userID=us.userID and st.storeID=us.saleStoreID order by us.saleID

它在shell中工作正常，但是如果我把这个语句放在我的iphone应用程序中，我会得到一个错误

/*
 * read items from the database and store in itemw
 *
 */
-(void)readItems {

if (!database) return; // earlier problems

// build select statement
if (!selStmt)
{
  const char *sql =  "select us.saleSpecificProduct,us.fAtMall,u.name,u.gender,st.storeName from UsersSale us,Users u,Stores st where u.userID=us.userID and st.storeID=us.saleStoreID order by us.saleID"; 
      if (sqlite3_prepare_v2(database, sql, -1, &selStmt, NULL) != SQLITE_OK)
    {
        selStmt = nil;
    }

当我执行应用程序时，在“sqlite3\u prepare\u v2”中出现错误 }

---

怎么了

也许可以尝试将参数放在单引号内

比如：

WHERE u.userID = 'us.userID' AND st.storeID = 'us.saleStoreID' ORDER BY us.saleID

此外，还应使用绑定来获取安全语句：

e、 g

NSString *strGet = @" . . . WHERE u.userID = ? AND st.storeID = ? ORDER BY us.saleID"

if(sqlite_prepare_v2(...) == SQLITE_OK)
{
    sqlite3_bind_int(stmtGet, 1, us.userID);
    sqlite3_bind_int(stmtGet, 2, us.saleStoreID);

    while(sqlite3_step(stmtGet) == SQLITE_ROW)
    {
        DatabaseDataObject *myDataObj = [[DatabaseDataObject alloc] init];

        myDataObj.objID = sqlite3_column_int(0);
        myDataObj.postcode = sqlite3_column_int(1);

        // add to parameter array of objects
        [myArr addObject:myDataObj];

        [myDataObj release];
    }
}