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Java Spring Boot-如何将application.yml属性定义为application.properties_Java_Spring_Amazon Web Services_Spring Boot_Amazon S3 - Fatal编程技术网
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Java Spring Boot-如何将application.yml属性定义为application.properties

java spring amazon-web-services spring-boot amazon-s3

Java Spring Boot-如何将application.yml属性定义为application.properties,java,spring,amazon-web-services,spring-boot,amazon-s3,Java,Spring,Amazon Web Services,Spring Boot,Amazon S3,我目前正试图用我的SpringBootWebApp设置一个s3存储桶，用于添加/删除图像 下面的指南使用了以下application.yml属性： amazonProperties: endpointUrl: https://s3.us-east-2.amazonaws.com accessKey: XXXXXXXXXXXXXXXXX secretKey: XXXXXXXXXXXXXXXXXXXXXXXXXX bucketName: your-bucket-name 如何在ap

我目前正试图用我的SpringBootWebApp设置一个s3存储桶，用于添加/删除图像

下面的指南使用了以下application.yml属性：

amazonProperties:
  endpointUrl: https://s3.us-east-2.amazonaws.com
  accessKey: XXXXXXXXXXXXXXXXX
  secretKey: XXXXXXXXXXXXXXXXXXXXXXXXXX
  bucketName: your-bucket-name
如何在application.properties文件中定义这些属性

非常感谢您的帮助，谢谢

在
应用程序中尝试将它们拆分为不同的行。属性
：

amazonProperties.endpointUrl= https://s3.us-east-2.amazonaws.com
amazonProperties.accessKey= XXXXXXXXXXXXXXXXX
amazonProperties.secretKey= XXXXXXXXXXXXXXXXXXXXXXXXXX
amazonProperties.bucketName= your-bucket-name
如果您使用的是spring云AWS maven依赖项 



org.springframework.cloud