Java 计算用户定义年数内四个季度的降雨量

我是Java新手，正在尝试做一项作业……但我现在感觉迷路了。我们还没有介绍数组，所以我们的词汇表有点有限

1.）修改当前代码，使其能够处理多年的降雨数据。为用户提供选项，以提供他们希望在计划中输入以进行评估的实际年数。该程序必须输出降雨量最多的年份（即第1年、第2年等）和总降雨量最少的年份

下面是我的代码：

import java.util.Scanner;

public class Test2OF
{
   public static void main(String[] args) 
   { 
      Scanner scan = new Scanner(System.in); 
      double[] rainfall = new double[4]; 
      double totalRainfall = 0.0; 
      double max = 0, min  = 0;
      int year = scan.nextInt();
      int maxQuarter = 1;
      int minQuarter = 1;

      // Prompt user for the number of years
      System.out.println("Enter the number of years: ");
      year = scan.nextInt();

      for (int i=0; i < year*4; i++) 
      { 
         System.out.print("Enter rainfall for quarter " + (i+1) + ": "); 
         rainfall[i] = scan.nextDouble(); 
         totalRainfall += rainfall[i]; 
         if (i == 0)
         {
            max = min = rainfall[i];
         }

         {
            if (rainfall[i] > max) {
               max = rainfall[i];
               maxQuarter = i + 1;
            }
            if (rainfall[i] < min) {
               min = rainfall[i];
               minQuarter = i + 1;
            }
         }
     }

   System.out.println("Total rainfall = "+totalRainfall); 
   System.out.println("Average rainfall = "+(totalRainfall / 4.0)); 
   System.out.println("Max quarter rainfall = "+ max);
   System.out.println("Min quarter rainfall = " + min);
   System.out.println("Max quarter rainfall = "+ maxQuarter);
   System.out.println("Min quarter rainfall = " + minQuarter);

   }//end main 
}//end class

我也不知道如何确定哪一年年底降雨量最多/最少

谢谢你的帮助！多谢各位

new double[4];  this is wrong.

若你们从用户那个里得到了大小，那个么你们为什么要初始化呢

---

用户提供尺寸后给出尺寸，如<代码>新双[年]

我立刻注意到的第一件事是

Int year = Scanner.nextInt();
Blahblahblah
year = Scanner.nextInt();

不要给年份赋值

Int year;
Year = scanner.nextInt();

至于其余的我不知道我是否想在这方面帮助你。帮助你是不道德的，因为这是为了学习。请注意，告诉你的教授你无法完成作业是完全可以的，他会比互联网提供更好的帮助

---

从iPad发送，因此请原谅拼写和大写错误

问题：

year*4

Scanner scan = new Scanner(System.in); 
  double[] rainfall; 
  double totalRainfall = 0.0; 
  double max = 0, min  = 0;
  int year = 0;
  int maxQuarter = 1;
  int minQuarter = 1;

  System.out.println("Enter the number of years: ");
  year = scan.nextInt();
  rainfall = new double[year*4]

public static void main(String[] args) 
{ 
   Scanner scan = new Scanner(System.in); 
   double[] rainfall; 
   int curyear = 0;
   double totalRainfall = 0.0; 
   double max = 0, min  = 0;
   int year = 0;
   int maxQuarter = 1;
   int minQuarter = 1;

   // Prompt user for the number of years
   System.out.println("Enter the number of years: ");
   year = scan.nextInt();
   rainfall = new double[year*4];
   for (int i=0; i < year*4 + 1; i++) 
   { 
       if((i % 4) == 0 && i != 0)
       {
            System.out.println();
            System.out.println("YEAR: " + ++curyear );
            System.out.println("Total rainfall = "+totalRainfall); 
            System.out.println("Average rainfall = "+(totalRainfall / 4.0)); 
            System.out.println("Max quarter rainfall = "+ max);
            System.out.println("Min quarter rainfall = " + min);
            System.out.println("Max quarter rainfall = "+ maxQuarter);
            System.out.println("Min quarter rainfall = " + minQuarter);
            System.out.println();
            if(i == (year*4))
                break;
       }

      System.out.print("Enter rainfall for quarter " + (i+1) + ": "); 
      rainfall[i] = scan.nextDouble(); 
      totalRainfall += rainfall[i]; 
      if (i == 0)
      {
         max = min = rainfall[i];
      }

      {
         if (rainfall[i] > max) {
            max = rainfall[i];
            maxQuarter = i + 1;
         }
         if (rainfall[i] < min) {
            min = rainfall[i];
            minQuarter = i + 1;
         }
      }


  }



}//end main 

您的

降雨量

只有4号，这意味着它只适合有4个季度的1年

解决方案：

year*4

Scanner scan = new Scanner(System.in); 
  double[] rainfall; 
  double totalRainfall = 0.0; 
  double max = 0, min  = 0;
  int year = 0;
  int maxQuarter = 1;
  int minQuarter = 1;

  System.out.println("Enter the number of years: ");
  year = scan.nextInt();
  rainfall = new double[year*4]

public static void main(String[] args) 
{ 
   Scanner scan = new Scanner(System.in); 
   double[] rainfall; 
   int curyear = 0;
   double totalRainfall = 0.0; 
   double max = 0, min  = 0;
   int year = 0;
   int maxQuarter = 1;
   int minQuarter = 1;

   // Prompt user for the number of years
   System.out.println("Enter the number of years: ");
   year = scan.nextInt();
   rainfall = new double[year*4];
   for (int i=0; i < year*4 + 1; i++) 
   { 
       if((i % 4) == 0 && i != 0)
       {
            System.out.println();
            System.out.println("YEAR: " + ++curyear );
            System.out.println("Total rainfall = "+totalRainfall); 
            System.out.println("Average rainfall = "+(totalRainfall / 4.0)); 
            System.out.println("Max quarter rainfall = "+ max);
            System.out.println("Min quarter rainfall = " + min);
            System.out.println("Max quarter rainfall = "+ maxQuarter);
            System.out.println("Min quarter rainfall = " + minQuarter);
            System.out.println();
            if(i == (year*4))
                break;
       }

      System.out.print("Enter rainfall for quarter " + (i+1) + ": "); 
      rainfall[i] = scan.nextDouble(); 
      totalRainfall += rainfall[i]; 
      if (i == 0)
      {
         max = min = rainfall[i];
      }

      {
         if (rainfall[i] > max) {
            max = rainfall[i];
            maxQuarter = i + 1;
         }
         if (rainfall[i] < min) {
            min = rainfall[i];
            minQuarter = i + 1;
         }
      }


  }



}//end main 

您需要计算指定年份数的季度数，然后使用

year*4

示例：

year*4

Scanner scan = new Scanner(System.in); 
  double[] rainfall; 
  double totalRainfall = 0.0; 
  double max = 0, min  = 0;
  int year = 0;
  int maxQuarter = 1;
  int minQuarter = 1;

  System.out.println("Enter the number of years: ");
  year = scan.nextInt();
  rainfall = new double[year*4]

public static void main(String[] args) 
{ 
   Scanner scan = new Scanner(System.in); 
   double[] rainfall; 
   int curyear = 0;
   double totalRainfall = 0.0; 
   double max = 0, min  = 0;
   int year = 0;
   int maxQuarter = 1;
   int minQuarter = 1;

   // Prompt user for the number of years
   System.out.println("Enter the number of years: ");
   year = scan.nextInt();
   rainfall = new double[year*4];
   for (int i=0; i < year*4 + 1; i++) 
   { 
       if((i % 4) == 0 && i != 0)
       {
            System.out.println();
            System.out.println("YEAR: " + ++curyear );
            System.out.println("Total rainfall = "+totalRainfall); 
            System.out.println("Average rainfall = "+(totalRainfall / 4.0)); 
            System.out.println("Max quarter rainfall = "+ max);
            System.out.println("Min quarter rainfall = " + min);
            System.out.println("Max quarter rainfall = "+ maxQuarter);
            System.out.println("Min quarter rainfall = " + minQuarter);
            System.out.println();
            if(i == (year*4))
                break;
       }

      System.out.print("Enter rainfall for quarter " + (i+1) + ": "); 
      rainfall[i] = scan.nextDouble(); 
      totalRainfall += rainfall[i]; 
      if (i == 0)
      {
         max = min = rainfall[i];
      }

      {
         if (rainfall[i] > max) {
            max = rainfall[i];
            maxQuarter = i + 1;
         }
         if (rainfall[i] < min) {
            min = rainfall[i];
            minQuarter = i + 1;
         }
      }


  }



}//end main 

编辑：

year*4

Scanner scan = new Scanner(System.in); 
  double[] rainfall; 
  double totalRainfall = 0.0; 
  double max = 0, min  = 0;
  int year = 0;
  int maxQuarter = 1;
  int minQuarter = 1;

  System.out.println("Enter the number of years: ");
  year = scan.nextInt();
  rainfall = new double[year*4]

public static void main(String[] args) 
{ 
   Scanner scan = new Scanner(System.in); 
   double[] rainfall; 
   int curyear = 0;
   double totalRainfall = 0.0; 
   double max = 0, min  = 0;
   int year = 0;
   int maxQuarter = 1;
   int minQuarter = 1;

   // Prompt user for the number of years
   System.out.println("Enter the number of years: ");
   year = scan.nextInt();
   rainfall = new double[year*4];
   for (int i=0; i < year*4 + 1; i++) 
   { 
       if((i % 4) == 0 && i != 0)
       {
            System.out.println();
            System.out.println("YEAR: " + ++curyear );
            System.out.println("Total rainfall = "+totalRainfall); 
            System.out.println("Average rainfall = "+(totalRainfall / 4.0)); 
            System.out.println("Max quarter rainfall = "+ max);
            System.out.println("Min quarter rainfall = " + min);
            System.out.println("Max quarter rainfall = "+ maxQuarter);
            System.out.println("Min quarter rainfall = " + minQuarter);
            System.out.println();
            if(i == (year*4))
                break;
       }

      System.out.print("Enter rainfall for quarter " + (i+1) + ": "); 
      rainfall[i] = scan.nextDouble(); 
      totalRainfall += rainfall[i]; 
      if (i == 0)
      {
         max = min = rainfall[i];
      }

      {
         if (rainfall[i] > max) {
            max = rainfall[i];
            maxQuarter = i + 1;
         }
         if (rainfall[i] < min) {
            min = rainfall[i];
            minQuarter = i + 1;
         }
      }


  }



}//end main 

publicstaticvoidmain（字符串[]args）
{ 
扫描仪扫描=新扫描仪（System.in）；
双[]降雨量；
int curyear=0；
两倍总降雨量=0.0；
双最大值=0，最小值=0；
整年=0；
int maxQuarter=1；
int minQuarter=1；
//提示用户输入年数
System.out.println（“输入年份：”）；
年份=scan.nextInt（）；
降雨量=新的双[年*4]；
对于（int i=0；i最大值）{
max=降雨量[i]；
maxQuarter=i+1；
}
if（降雨量[i]

雨水中的元素不足。你需要4个元素。在你知道年数之前不要计算它的大小。嘿，谢谢！我对我的代码进行了调整，我可以收集正确数量的数据（即2年=8个季度）。你知道我如何为第一至第四季度分配“第一年”，然后为第五至第八季度分配“第二年”（等等）吗。再次感谢你！别担心。我感谢你的帮助！