Java StringBuilder是否根据索引输出?
若第一个输入是“狗”,第二个输入是“狼”,第三个输入是“猫”。结果如下:Java StringBuilder是否根据索引输出?,java,tostring,stringbuilder,Java,Tostring,Stringbuilder,若第一个输入是“狗”,第二个输入是“狼”,第三个输入是“猫”。结果如下: Dog | Wolf | Wolf | Cat | Cat | Cat | 我的forloop是否导致此循环过于频繁 public class LabTextManipulation { public static void main(String[] args) { Scanner input = new Scanner(System.in); ArrayList<Stri
Dog | Wolf | Wolf | Cat | Cat | Cat |
我的forloop是否导致此循环过于频繁
public class LabTextManipulation {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
ArrayList<String> parks = new ArrayList<String>();
String enteredPark;
StringBuilder sb = new StringBuilder();
boolean stop = true;
while (stop == true) {
System.out.println("Please enter your favorite National Park or Done to stop: ");
enteredPark = input.nextLine();
if (!"Done".equalsIgnoreCase(enteredPark)) {
parks.add(new String(enteredPark));
for (int i = 0; i < parks.size(); i++) {
sb.append(enteredPark + " | ");
}//end for
} else {
stop = false;
}
}
String nationalParks = sb.toString();
System.out.println(nationalParks);
}
}
实际:
" Dog | Wolf | Wolf | Cat | Cat | Cat |"
这是问题的根源
for(int i = 0;i < parks.size(); i++ ) {
sb.append(enteredPark + " | ");
}
一直都是这样谢谢,根本不需要forloop。谢谢@m、 安特科维茨
for(int i = 0;i < parks.size(); i++ ) {
sb.append(enteredPark + " | ");
}
if(!"Done".equalsIgnoreCase(enteredPark)) {
parks.add(enteredPark); // also don't create new String here
sb.append(enteredPark + " | ");
}